Recent content by Toodles
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Max current densities in a conducting medium
Thanks for this reply. Why do you say the top to bottom resistances are high and the side to side resitances are low? I would expect due to nonlinear effects that since the current is so large (assumedly exceeding the max current density of the conductor) in the side to side electrodes, that you...- Toodles
- Post #11
- Forum: Electrical Engineering
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Max current densities in a conducting medium
Rotational current would be one with nonzero curl: $$\nabla \times \mathbf{j} \neq 0$$ And I am referring to the standard Maxwell equations; in particular Faraday's law $$-\frac{\partial \mathbf{B}}{\partial t} = \nabla \times \mathbf{E} $$ and Ohm's law $$\mathbf{j} = \sigma \mathbf{E} $$. If...- Toodles
- Post #10
- Forum: Electrical Engineering
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Max current densities in a conducting medium
Hi everyone, Thanks for the replies. First off, I unfortunately can not give out a much better explanation of the problem nor can I elaborate on the rule of the magnetic field, but for my question here, it can be considered to not exist. Sorry! I understand what the current should do...- Toodles
- Post #8
- Forum: Electrical Engineering
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Max current densities in a conducting medium
Sorry, I should change the figure. The electrodes are supposed to be touching the conducting medium. So there are infinitely large current right at the joining point of the electrodes (essentially a dipole here).- Toodles
- Post #3
- Forum: Electrical Engineering
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Max current densities in a conducting medium
Hi, I am looking for some information regarding maximum current density in conducting mediums, such as a conducting fluid. Say that we have a setup like the figure that I have attached. We are looking down on a conducting medium with a uniform magnetic field coming out of the page and the...- Toodles
- Thread
- Conducting Current Max Medium
- Replies: 10
- Forum: Electrical Engineering
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Difference between normal viscous stress and pressure
This is what I have always thought, and I guess just more or less accepted. However, I am thinking about it now and have become confused. Say that you have a velocity gradient ∂u/∂x, which doesn't imply incompressibility. This will result in a normal viscous force of 2μ∂u/∂x according to stress...- Toodles
- Post #9
- Forum: Aerospace Engineering