Thanks for the help.
In high school, math was taught as being a collection of tools to use to solve some problem. In universtiy I guess they figure we know how to use some of those tools, now we need to understand how some of those tools were made and why they actually work.
Thanks, I think I'm getting it now.
Based on your previous example, I wrote up my own even simpler example:
Hopefully this is correct:
The limit as x approaches 2 of 2x = 4.
For epsilon > 0 we need to find a delta > 0 such that 0 < |x - 2| < delta then |2x - 4| < epsilon.
So we...
The problem I have is that the textbook diagrams seem to imply that for f(c) = L, epsilon is a single value (the number of units above and below L) and delta is a single value (the number of units right and left of c). The diagrams seem to imply that f(c+delta) = L + epsilon and f(c-delta) = L -...
Hi, I have a question about the epsilon / delta definition of limits, for example the limit of x as it approaches c for f(c) = L.
As I understand it, epsilon is basically the number of units on either side of L on the y-axis that makes a range between L + epsilon and L – epsilon with L being...
I know that's the quotient rule. My problem is that when I apply it to my problem, I can't seem to get the simplified answer from the book.
For example, if the denominator is (x - 2)^3 and it's squared, shouldn't that produce (x - 2)^6. Therefore, how could the answer have a denominator of...
Hi,
I'm struggling to understand how to find the derivative of something like this...
[(2x - 1)^2] / [(x - 2)^3]
The answer in my book says it is supposed to be [-(2x - 1)(2x + 5)] / [(x - 2)^4]
How do I use the chain rule with the quotient rule at the same time?
I even multiplied...
My son in grade 5 had to do an experiment to make insulated cups using different materials. He made one using insulated Styrofoam pieces from ripped up cups and one using cotton balls. He packed Styrofoam pieces into a large cup and placed a smaller cup inside the larger cup and packed more...
OK,
Steve paints 1 house in 30 hours or 1/3 house in 30/3 = 10 hours
That means that Dale has to paint the other 2/3 of the house in the 10 hour period.
Working backwards for Steve, to get from the 10 hours together to his single total, we multiply 10 by 3/1 = 30 hours.
So, for...
My mind is blank for some reason as I can't seem to figure out how to set up this problem...
It takes Steve and Dale together 10 hours to paint a house.
Steve takes 30 hours by himself.
How long would it take Dale to paint the house my himself?
Thanks...