Recent content by Trade

I would, but my prof has specifically stated that it can't be a hand drawn graph.

0.15 is the coefficient of friction. So in this case the frictional force will be, F(friction) = F(gravity)(.15) Try drawing a free body diagram with the applied force (that's the 150N it's talking about) and the force of friction and try to figure it out. Remember F=ma

Homework Statement Evaluate the work done W = op∫ F\bulletdr By the two dimensional force F = (x2, 2xy) along the following paths from the origin to the point P(1,1): 1) This path goes along the x-axis to the point Q(1,0) and then directly up to the point P(1,1). 2) Along the path y...

Awesome, I think I have it from here. Thanks.

Okay, so I end up with something along the lines of... K [x, 2y, 3z] = - [dU/dx, dU/dy, dU/dz] and then we integrate U = -k [ (1/2)x2, y2,(3/2)z2] Would it be proper to add a constant at the end of each part, noting that it's terms of the other two variables? Something like U = -k [ (1/2)x2...

Homework Statement The problem basically asked me to check if a given force was conservative and if it was conservative, also find the potential energy. F = k(x,2y,3z) Homework Equations (\nabla X F) = Curl of F U = Integral of F 3. attempt So the force is clearly conservative as the curl...