Recent content by TrifidBlue

I figured it out, thanks for your help :D

bcrowell, I'm sorry, for putting _illegal online copies. WannabeNewton, I'll try again, I didn't notice it was an exercise. thanks.

You can download it as PDF [deleted copyright-violating link - bcrowell] Or as djvu file [deleted copyright-violating link - bcrowell]

http://books.google.com/books?id=qhDFuWbLlgQC&lpg=PP1&pg=PA11#v=onepage&q&f=false" Until he arrives at eq. 1.5 I don't understand the steps, can anyone explain it? thanks

and that's what I've said :confused: thank you

Thank you very much,Tusike ^_^

thaaaaaaaaaaaaaank you! please check the steps (n+1) = k (n^2 -n +1) = k n^2 -n +1 = n+1 n(n-2)=0 n=0 , k=1 (not prime) n=2 , k=3

k^2= (n+1) [ n(n-1) +1] that is k^2 = n (n+1)(n-1) + (n+1) right?

I tried with these two clues, k^2 = (n+1)(n^2 -n+1) k = sqrt [(n+1)(n^2 +n+1)] and from clue (1) k^2 can be divided by k^2 , 1, k and -k but I don't know how to connect the information together to get the answer :(

thanks I'll try these hints

Homework Statement If k is a prime number find all k that satisfy k²=n³+1 n is not a prime number Homework Equations I really have no idea, use any suitable one The Attempt at a Solution all prime numbers are odd except 2. n must be positive natural number n³ = k² -1 =...

thank you very much Tedjn, Gerenuk and Gib Z and extra thanks for you Gib Z for the details

I hope this the right place to post my question... should it be, "we can define a as half the sum of distances..."? please correct and explain if I'm mistaken thanks

How can this be proved? I really in need to know it, as I'm working on a derivation of Kepler's laws, but I'm stuck at this point :confused::cry::frown: ... Thanks in advance

Thanks a lot to all of you Fredrik, Altabeh, torquil, bcrowell I've already started studying special relativity, differential equations and linear algebra so I suppose the next step would be differential geometry and I thought I'll spend long time to find good books but you told me...