A pair of relaxed eyes of a patient have a refractive power of 48.5 diopters.
a) is this person near or far sighted?
I think its far sighted because of the short focal length.
b) Find the near point of this person. (The retina is 2.4cm from the lens).
Ok, so the f=.02 and I'm...
Ok, I need a lot of help on this one. A single conducting loop of wire has an area of 7.4*10^-2 m^2 and a resistance of 110 ohms. Perpendicular to the plane of the loop is a magnetic field of strength 0.18 T. At what rate (in T/s) must this field change if the induced current in the loop is...
Ok, an ion experiences a magnetic force of 6.2X10^-16 N when moving in the positive x direction, but no force when moving in the positive y direction. What is the magnitude of magnetic force exerted on the ion when it moves in the x-y plane along the line x=y? Assume the ions speed is the same...
1. For http://www.pen.eiu.edu/~cuemc4/circuit.bmp picture.. Calculate the potential at point D.
2. I 15-V battery is connected to three capacitors in series. The capacitors have the following capacitances: 4.5microFarads, 12.0microFarads, and 32microFarads. Find the voltage across the...
1. For http://www.pen.eiu.edu/~cuemc4/circuit.bmp picture.. Calculate the potential at point D.
2. I 15-V battery is connected to three capacitors in series. The capacitors have the following capacitances: 4.5microFarads, 12.0microFarads, and 32microFarads. Find the voltage across the...
For part 1 I just don't see how to get the q for the proton. I just stumbled upon it for the other part.
FOr part 2 the q value is definitely not in my book. I looked in all the appendices and everything.
For part 3 you're saying that V = ED?
Ok I have a couple questions here.
1. Calculate the speed of a proton and an electron after each particle accelerates from rest through a potential difference of 190V.
I think I got the part of the electron because I randomly came across the energy value of an electron. The equation I'm...
Ok here's the deal. The problem gives me this wave function:
y= (15cm) cos[(pi/5cm)x - (pi/12s)t]
I undserstand that 15cm represents the amplitude, 5cm represents the wavelength, and 12s represents the T. What I don't get is that the standard wave function is in this form:
y(x,t)= A...