How Does Magnetic Force Affect an Ion Moving Along the Line x=y?

AI Thread Summary
An ion experiences a magnetic force of 6.2X10^-16 N in the positive x direction and no force in the positive y direction, indicating the magnetic field's orientation. To determine the magnetic force when the ion moves along the line x=y, the angle θ is 45 degrees. The force can be calculated using the equation F = qvB sin θ, where the components of velocity in the x and y directions must be considered. It's essential to express the velocity components in terms of the overall speed using the Pythagorean theorem. Ultimately, the new angle of the ion's velocity relative to the magnetic field must be established to find the magnitude of the magnetic force in this scenario.
triplezero24
Messages
16
Reaction score
0
Ok, an ion experiences a magnetic force of 6.2X10^-16 N when moving in the positive x direction, but no force when moving in the positive y direction. What is the magnitude of magnetic force exerted on the ion when it moves in the x-y plane along the line x=y? Assume the ions speed is the same in all cases.

I know that for this problem F=qvB sin theta. Because the ion travels on the line x=y, then the theta angle is 45. Other than that I have no clue. :confused:

Thanks again for any help. :smile:
 
Physics news on Phys.org
break it up into an x component and a y component velocity and find the force for each.
 
It says the speed is the same in all cases.
 
It says the speed is the same in all cases.
so what?
break it up into an x component and a y component velocity and find the force for each.
for sure v_x and v_y is not equal to v... but can you find v_x and v_y in term of v using the P******* theorm? (really have no idea how to spell that word)
 
triplezero24 said:
It says the speed is the same in all cases.

StatusX means use vector notion instead of F=qvB sin theta.

<br /> F= q \vec{v} \times \vec{B} =( v_y B_z - v_z B_y )\hat{x} + (v_z B_x - v_x B_z )\hat{y} + (v_x B_y - v_y B_x)\hat{z}<br />

Some terms will be zero though if \vec{B} is perendicular to \vec{v}
 
triplezero24 said:
Ok, an ion experiences a magnetic force of 6.2X10^-16 N when moving in the positive x direction, but no force when moving in the positive y direction.
This should tell you two things:
(1) The direction of the magnetic field (B)
(2) The value of qvB (apply F = qvB sin \theta, where \theta is the angle between v and B)

What is the magnitude of magnetic force exerted on the ion when it moves in the x-y plane along the line x=y? Assume the ions speed is the same in all cases.
Once you've figured out (1) and (2), all you need to find your answer is to again apply F = qvB sin \theta with this new angle. What angle does the ion velocity make with the B field when it travels the line x=y?
 
Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Back
Top