# Recent content by truettct

1. ### Engineering Simple Circuit: Find v1 and v2

Ok thanks so much for the help. I have many problems on my homework like this one and I didnt want to start the others one knowing I was getting the wrong answer. I was solving the equations wrong and I went back and got it figured out. Thanks for the explanation. What is the program you used...
2. ### Engineering Simple Circuit: Find v1 and v2

I must be doing something wrong with my algebra, because I still cannot come up with the right answer.
3. ### Engineering Simple Circuit: Find v1 and v2

Simple Circuit: Find "v1" and "v2" Homework Statement Using the circuit attached find the value of "v1" and "v2". The values for Is1=2.9A R1=124 ohm R2= 24 ohm R3= 240 ohm R4= 380 ohm Is2= 3.2A. Homework Equations I approached this problem by putting R3 and R4 in...
4. ### P-N Junction Diode Problem HELP

Homework Statement A pn junction diode has saturation current Is= 1e-12 A. What is the current through this diode if a positive voltage 0.68 V is applied to it? (Unit: A) Homework Equations I=Is(e(Vd)/(Vt))-1) The Attempt at a Solution I dont even know where to begin, but i just...
5. ### Capacitance of this capacitor

Homework Statement A capacitor stores 0.12 J energy when connected to 6 V voltage source. What is the capacitance of this capacitor? (UNIT:uF) I am just not sure how to go about answering this question. The formula for capacitance is C=(Q/V), but I am not sure how to incorporate energy...
6. ### Power Delivered To The Load

1. Homework Statement The battery has 1.35 V output voltage and 0.15 Ohm internal resistance. The battery is used to boot a small electric motor with 285 Ohm resistance. Find the power delivered to the motor. What the power will be if we use two batteries of this type in series? 3...

Thanks.
8. ### Voltage Divider Problem

This is the problem. Given that Vg is 210 V, R1 is 15.5 kOhm, R2 is 66 kOhm and RL is 157.5 kOhm, find the voltage "v0" (Hint: Use the voltage divider concept.) My attempt at the problem was to combine R1 and R2 through series and use RL as R2 in the voltage divider formula. The answer...