Recent content by TsuinRyu

So the flow rate data is the rate of change of volume per second. It is measuring the amount of fluid entering the cylinder per second? Sorry I'm just really confused

The course is called Bio-engineering in Urology and this is supposed to be urine flow rate data. Right so at hmax I believe that Qin = Qout Qout=vA, where v=\sqrt{2gh} and A=\pir2 therefore Qout=\pir2\sqrt{2gh} I also know that Q=\frac{dV}{dt}...using this for Qin...

I have no course notes, hence the difficulty in solving this. The data we have is the flow rate into the cylinder and I have the diameter of the cylinder D=5cm and the diameter of the hole at the bottom of the cylinder d=0.5cm As I understand it you have to make the assumption that...

Unfortunately I am a medic and have done no physics in the last 6 years. But I assume the flow out is dependent upon gravity acting upon the body of fluid in the cylinder? I've seen the equation v^2=2gh (where h is change in height) but I can't work out how to solve it as the flow rate I have...

Hi, so I am trying to calculate the maximum height that would be achieved in a cylinder and have been give only the flow rate. The cylinder itself is a simple straight sided cylinder, the opening at the top has a diameter of 5cm and the hole at the bottom has a diameter of 0.5cm...

So I'm a bit unsure if I should start a new thread, but I have a similar problem with similar data. I cannot understand how to apply Bernoulli's equations to the flow rate to solve for height. Any help would be appreciated. Examples would be very helpful. Thank you