Recent content by turtledove

awesomee, thanks !

oh ! ok, i was thinking about that too, but i don't know which distances to use? this would be my attempt: Fthrust x d + 0.5kx^2 = mgh + 0.5mv^2 (177)(0.38) + 0.5(385)(0.26)^2 = (10.2)(9.8)(0.38) + 0.5(10.2)v^2 v = 2.88 m/s This answer makes sense, because it is greater than the speed...

Homework Statement A 10.2 kg weather rocket generates a thrust of 177.0 N. The rocket, pointing upward, is clamped to the top of a vertical spring. The bottom of the spring, whose spring constant is 385.0 N/m, is anchored to the ground. Initially, before the engine is ignited, the rocket sits...

would i just keep it as Vfy = 19sin52.5 ? what other values need to be incorporated? I am so confused with this question!

Ok, I tried something different: Vfx = 19.4cos52.5 = 11.8 m/s Vfy = 19.4sin52.5 + sqrt 2(60.3)(9.8) = 15.4 + 34.37 = 49.76 m/s V^2 = (Vx)^2 + (Vy)^2 = 51.1 m/s This is wrong again :(

Hmm...does that mean it is simply 19.4 m/s?

Homework Statement A boy kicks a rock off a cliff with a speed of 19.4 m/s at an angle of 52.5° above the horizontal. The rock hits the ground 5.41 s after it was kicked. a) How high is the cliff? (60.3 m) b) What is the speed of the rock right before it hits the ground? c) What is...

Homework Statement A 68.7 kg spacewalking astronaut pushes off a 653.0 kg satellite, exerting a 153.0 N force for the 0.763 s it takes him to straighten his arms. How far apart are the astronaut and the satellite after 9.36 min? Homework Equations d = vit + 1/2 at^2 The Attempt...