Recent content by tvavanasd

Try Misumi USA. I don't think that carbon fiber is the best material for a shaft. Keep the "slide" bearing length relatively long to avoid binding. Consider a trunnion style pivot if geometry will allow it.

Preloading eliminates/minimizes slack; ideally the rope will always be under tension. I just noticed that the load mass is 2000 kg. The preload on the wire should likely be at least 1000 lbf (per above you need a full loop of rope) in order to eliminate the slack. Preload doesn't...

Either preload the wire rope as suggested (loop all the way around and pre-tension), or add a 2nd screw jack and tie them together with sprockets and chain (or gearboxes and shaft). Might be simpler to change to purchased screw jacks (Duff Norton, Joyce Dayton, Nook) and tie their inputs...

Not quite, it should be: G = L * (Vy / Vx) - L or more simply: G = L * [(Vy / Vx) - 1] To check: If Vy = Vx, G should be 0. Looks like I got D and G mixed up previously when I indicated that Vy = 15 m/min (I was wrong).

Yes, G = D - L Sorry, what was Vy? It must be 15 m/min, although I don't think you mentioned it. You can either use L = actual product length (assuming no gap) or Leff = effective product length which is equal to product length + initial gap. Yes, the final gap is proportional to product...

FYI, I just changed the conveyor speed variables names to Vx and Vy. So the time is obviously the product length divided by upstream speed Vx, or: t = L/Vx Jumping ahead, in the same time "t", the leading edge of the leading product will travel a distance: D = Vy * t (Yes, I did just...

A very simplified approximation of product gap can be calculated if you assume infinite product acceleration from one conveyor to the other. If you are interested, I will help you find the solution, but I can't just give it to you. Vx = upstream conveyor speed (m/min) Vy = downstream...

It's a little tougher than that. Draw a diagram showing the swing rope length, height change and theta. Note that: h used in potential energy equations is change in height. h used in trig is hypotenuse. For clarity (and to avoid confusion), consider using "hyp" for hypotenuse. I think that...

Yes, when the grandfather holds her at the top, all energy is potential. Assuming negligible loss to drag and friction, at the bottom of the swing motion all energy should be kinetic.

Everything. The angle isn't really important yet. How about calculating the initial starting height (potential) based on the known kinetic energy. Can you list both the potential and kinetic energy equations?

Along with work, have you studied potential and kinetic energy?

Your problem may be practically solved most simply by downloading software from Festo or another manufacturer of pneumatic components.

Yes, you are correct, torque is measured/ calculated about a pivot or axis. Search the web for an accurate definition (Wiki is usually a good start). Always, check a few sources to confirm consistency/ reliability. One thing to consider is that torque doesn't just appear out of nowhere. It...

No, that is not true. If you need to pull with a force of 7500 lb by applying torque through a 1" shaft, you must apply 3750 in*lb of torque to the shaft. The same 3750 in*lb of torque will only result in 750 lb of force to the cable. The torque in the shaft is the same, the force available...

Your assumption that changing shaft diameter affects torque is incorrect. Keep showing units with answers to all calculations. In the chain drive, calculate chain tension (force) using the equation: force = torque / distance In this case, the distance will be the radius of the sprocket or...