Recent content by uasaki

Homework Statement You start out with a bag that contains either a red marble or a green marble with equal probability. Then, a red marble is added to the bag. If I draw out a red marble the first time, what is the probability of drawing out a green marble the second time? Homework...

That makes sense to me intuitively, but I'm not sure how I would go about proving that the strategy is optimal. Do I just need to compare the probability that Robin Hood will miss again if he intentionally misses one of the first four shots vs. the probability that Robin Hood will miss again if...

Thanks for the reply. Is there any reason why I don't need to consider the case(s) in which Robin tries to purposefully miss the first shot and make the rest, or purposefully miss the second shot and make the rest, etc?

Homework Statement Although Robin Hood gets a bullseye with probability 0.9, he finds himself facing stiff competition in the tournament. To win he must get at least four bullseyes with his next five arrows. However, if he gets five bullseyes, he risks exposing his identity to the sheriff...

Oh, wait. If we place a short from terminals a and b, then there is no voltage drop across that wire. So, we don't need to add $$V_{oc}$$ in mesh 2's KVL.

Thanks for the help. So for the short circuit current I placed a wire in-between terminals a and b. Then, I just used mesh analysis to solve for the circuit. The KVL for mesh 1 is $$4I_{1} + 4(I_{1} - I_{3}) + 8(I_{1} - I_{2}) + 48 = 0 \Rightarrow 16I_{1} - 8I_{2} - 4I_{3} = -48$$ The KVL...

Oops, my bad. The two 8-ohm resistors in parallel should be produce a 4-ohm resistor. Was that the only mistake in my calculation?

Oh, ok. So, if we start at the end opposite the output ports, then the two 4-ohm resistors are in series, so we can combine them to get an 8-ohm resistor. Then, that 8-ohm resistor is in parallel with the 8-ohm resistor in the circuit, so we can combine them to get an 8-ohm resistor. That 8-ohm...

Homework Statement The circuit diagram is attached below. We're supposed to a) find the Thevenin equivalent circuit and b) find the value of Rl (the load resistor) so that the current flowing through it is 0.5A. Homework Equations The Attempt at a Solution Since the circuit...

But isn't the loop current equivalent to the current that flows through the 4-ohm resistor? Edit: Nevermind, I think I got it. The current through the resistor in the original CS + R configuration would just be 2A - (-0.6) = 2.6 A.

The current through the circuit would just be the total voltage / total resistance. Then, I can just multiply the loop current by the value of the resistor. The problem is that the answer that I get from doing that is different than the answer that circuitlab is giving me. Also, wouldn't the...

It looks like a circuit with four voltage sources and four resistors in series. I can simplify this circuit and use the voltage divider rule to find Va but I don't think my polarities are correct. For my final circuit, I have a 8V source (- at the top, + at the bottom) in series with a 4-ohm...

I'm not really sure how to find the loop current. Would writing KCLs at each of the nodes and/or a KVL around the resistors help me to find the loop current? Thanks for the help.

Ok, does the polarity of the voltage drop across the resistor change how we do source transformation and/or apply the voltage divider rule in any way?

Thanks for the help guys. I originally thought that the voltage drop across the resistor in the CS + R configuration was equal to the voltage drop across the resistor in the VS + R configuration. I didn't realize that the voltage drop and current across the resistor changed when you performed a...