Recent content by UMDstudent

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    What Is the Correct Internal Temperature of a Sealed Box with a Lightbulb?

    Right but its asking for the cross sectional area of a cube. If i use A = s^6 : (.22)^6 = .000113 = very low number. Once this is plugged into the above equation, I get a HUGE number for degrees Celsius which makes no sense. That HUGE number = 539,019 degrees Celsius. -UMDstudent
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    What Is the Correct Internal Temperature of a Sealed Box with a Lightbulb?

    Homework Statement A cubical box 22cm on a side is constructed from 1.3cm -thick concrete panels. A 100 W lightbulb is sealed inside the box. What is the air temperature inside the box when the light is on if the surrounding air temperature is 20 C? Homework Equations rate of heat transfer...
  3. U

    What is the temperature at the end of the process ?

    ^^^^Exactly, so here's how you set it up (hope this helps) T2 = ( P2 / P1 ) * T1 *Don't forget to convert to Kelvins during the calculations and remember to subtract 273 afterwards. For Part B, my question to you is : Is any Work done during a Isochoric process...
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    Interference of Two Sound Waves: Phase Difference & Intensity

    I'm working on the same question; I'm actually a little confused myself, however, let me show you what I've done so far and hopefully someone else can elaborate: Part A : Using the formula : Phase Difference = 2pi*(deltaX/Wavelength) + PhaseDiffConstant. : 2pi*(4meters/15meters) = 8pi/15...
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    Frequency, Time, Wavelength = Doppler Effect

    [SOLVED] Here is the complete work through (in case others need help) Part A : Time = Distance / Velocity T = (3 meters / 2.99 * 10^8) + (10 meters / 2.26 *10^8) = 5.43 * 10^-8 seconds Part B : Time = Distance / Velocity T = (3 meters / 343 ) + (10 meters / 1480 ) = .02 seconds. 343...
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    Frequency, Time, Wavelength = Doppler Effect

    I understand I should check my work over, and I did; but sometimes it takes someone else to inform you of that error. When I did the unit conversion, I wasn't paying attention and believe me, I recognized that C was a little funny. This is why I posted because if i was 100% confident, why...
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    Frequency, Time, Wavelength = Doppler Effect

    Homework Statement A small homemade firework goes off 3 meters about the surface of the water where a person is diving. The diver is 10 meters below the surface of the water. (a). How much time passes from the instant the firework goes off until the diver sees it? (b). How much time...
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    How Does Bernoulli's Equation Determine the Height of Mercury in a U-Tube?

    SOLVED: ehild, Thank you for taking the time to review my work and locate my error. The final answer comes out to be .044073 meters = 4.4 cm. Again, Thanks -UMDstudent
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    How Does Bernoulli's Equation Determine the Height of Mercury in a U-Tube?

    [SOLVED] Bernoulli's equation & U-Tube Homework Statement Air flows through this tube at a rate of 1200 cm^3/s . Assume that air is an ideal fluid. What is the height of mercury in the right side of the U-tube? Homework Equations Bernoulli's Equation (P1 + 1/2*rho*V1^2 +...
  10. U

    What length of steel is above the surface?

    nvm, I figured this out. I needed to just convert that answer back to centimeters and then subtract that *23 centimeters from the original 80.Thanks.
  11. U

    What length of steel is above the surface?

    nvm, I figured this out. I needed to just convert that answer back to centimeters and then subtract that *23 centimeters from the original 80. Thanks.
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    What length of steel is above the surface?

    [SOLVED] What length of steel is above the surface? Homework Statement A 10-cm-diameter, 80.0 -tall steel cylinder (density of steel 7900) floats in mercury. The axis of the cylinder is perpendicular to the surface. What length of steel is above the surface? Homework Equations Free...
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    Calculating Amplitude and Energy in a Damped Oscillator: A Homework Question

    BUMP... I need some clarification to see if I am correct?
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    Calculating Amplitude and Energy in a Damped Oscillator: A Homework Question

    U = 1/2 (82.1)(.102)^2 k = omega^2 * Mass = 82.1 U = .427 ------------------------------------------------ K = 1/2 mv^2 K = 1/2 (.52)(4.01)^2 K = 4.18 v = square root (k/m * A) ------------------------------------------------ Total Energy = K + U TE = 4.61 64% of TE = 2.95. TE - 64% =...
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    Calculating Amplitude and Energy in a Damped Oscillator: A Homework Question

    The kinetic energy at the turning point (the maximum displacement from equilibrium) would be equal to zero.U = 1/2*K*A^2. Wouldn't this be the total energy of the equation?
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