Recent content by Umphreak89

  1. U

    Frictional coin sliding on turntable

    (.005)(9.8)(.8) = (.005)(.22)(ω)^2 => (9.8)(.8) = (.22)(ω)^2 => 7.84 / .22 = ω^2 => ω = (7.84 / .22)^(1/2) = 5.969 then I'm not sure how to convert this to rpms.. but, 5.969 / r = 27.134, where r = .22, which isn't right
  2. U

    Frictional coin sliding on turntable

    m(ω * r)^2 / r simplifies to => m(r)(ω)^2 so, mg * µs = m(r)(ω)^2 (?)
  3. U

    Frictional coin sliding on turntable

    A 5.0 g coin is placed 22 cm from the center of a turntable. The coin has static and kinetic coefficients of friction with the turntable surface of µs = 0.80 and µk = 0.50. What is the maximum rpm that the turntable could speed up to without the coin sliding off? m = .005 kg r = .22 m...
  4. U

    Frictional coin sliding on turntable

    A 5.0 g coin is placed 22 cm from the center of a turntable. The coin has static and kinetic coefficients of friction with the turntable surface of µs = 0.80 and µk = 0.50. What is the maximum rpm that the turntable could speed up to without the coin sliding off? m = .005 kg r = .22 m µs = 0.8...
  5. U

    How Far Down the Slope Does the Arrow Land?

    Homework Statement An Archer standing on a 15 degree slope shoots an arrow 20 degrees above the horizontal. how far down the slope does the arrow hit if it is shot with a speed of 50m/s from 1.75m above the ground Homework Equations The Attempt at a Solution y component = 50 * cos(20 + 15) -...
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