Recent content by ussjt

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    What is the angular speed of the slingshot stone at the moment of release?

    wouldn't the velocity just be the change in distance over time? 30r/t
  2. U

    What is the angular speed of the slingshot stone at the moment of release?

    ok I understand that x2 = 30*r. x2 = v1t + .5at^2 x2 = v1t x2/t = v1 30r/t = v1 then use: Vt = rw I am doing this right?...I am not sure because I am tired right now.
  3. U

    What is the angular speed of the slingshot stone at the moment of release?

    but when trying to get the horizontal distance...there are 3 unknowns. V_1 V_2 and X_2. SO how fo you get it as a function of time?
  4. U

    What is the angular speed of the slingshot stone at the moment of release?

    I am having problems figuring out the horizontal distance. Once I have that I can use that to determine the radius and I have the time already.
  5. U

    What is the angular speed of the slingshot stone at the moment of release?

    ok I figured out the time. I am a little confused by what you mean.
  6. U

    What is the angular speed of the slingshot stone at the moment of release?

    One type of slingshot can be made from a length of rope and a leather pocket for holding the stone. The stone can be thrown by whirling it rapidly in a horizontal circle and releasing it at the right moment. Such a slingshot is used to throw a stone from the edge of a cliff, the point of release...
  7. U

    Gymnast's Floor Routine: Angular Velocity & Time

    A gymnast is performing a floor routine. In a tumbling run she spins through the air, increasing her angular velocity from 3.00 to 4.65 rev/s while rotating through one-half of a revolution. How much time does this maneuver take? ok I understand that I am going to be using one of the...
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    How fast is the skier going just before she lands?

    do I need the x? Because once it goes into free fall it is only accelerating in the y direction. "you can use energy conservation to find the final speed" I am confused by what you mean.
  9. U

    How fast is the skier going just before she lands?

    An extreme skier, starting from rest, coasts down a mountain that makes an angle 25.0° with the horizontal. The coefficient of kinetic friction between her skis and the snow is 0.200. She coasts for a distance of 13.4 m before coming to the edge of a cliff. Without slowing down, she skis off the...
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    Chain Rule Help: Solving (g o f)'(4) with f'(8)=5, g'(8)=3, f(4)=8, and g(4)=10

    the way our TA showed up, the answer ought to be: (7x^3/6)*(y/2)^(1/3)...but my answer must be in terms of x...so could someone please tell me if I went wrong somewhere or how to make it all in terms of x (by x I mean I can't have that "y"). Here are my steps: f '(2x^3)(6x^2)= 7x^5 f...
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    Chain Rule Help: Solving (g o f)'(4) with f'(8)=5, g'(8)=3, f(4)=8, and g(4)=10

    what about this type of problem: For a given functionhttps://webwork2.math.ohio-state.edu/courses/math151wi06sm/tmp/png/Hmwk5/696680/kopko.4-prob5image1.png consider[/URL] the composite function...
  12. U

    Chain Rule Help: Solving (g o f)'(4) with f'(8)=5, g'(8)=3, f(4)=8, and g(4)=10

    have not tried because I don't know how to set up the problem...I don't really care about the answer I just want to know how you go about setting up these kinds of problems because I have a quiz tomorrow. I figure the first step is g(f(x)) so g'(f(x))*f'(x) g'(8)*f'(x) 3*f'(x)
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