Recent content by VaioZ

Homework Statement In the figure, block 1 of mass m1 = 1.8 kg and block 2 of mass m2 = 1.4 kg are connected by a string of negligible mass. Block 2 is pushed by force Upper F Overscript right-arrow EndScripts of magnitude 18 N and angle θ = 34°. The coefficient of kinetic friction between each...

lol I am such a stupid one is my c.) and d.) right?

Homework Statement You throw a ball vertically upward from the roof of a tall building. The ball leaves your hand at a point even with the roof railing with an upward speed of 15.0 m/s; the ball is then in free fall. On its way back down, it just misses the railing. Find (a) the position and...

Oh okay that make sense to prove that it I can get 0 m/s thank you!

for letter B finding the in instantaneous velocity. I don't need to derive it because it is already in v(t) I'll just plug t = 10 s into v(t)=(7.20m/s^2)t-(0.720m/s^3)t^2 I got 0 m/s hmmm I find it odd to get 0 in instantaneous velocity

I meant to say when you're getting x(t) the units should m or meters right? So I answered 120 m. Then I use average velocity = ΔX/ΔT soooo 120 m / 10 s = 12 m/s right? This is for letter A

First I was frustrated that I can't get -72 m which consuming all my time so I decided to post my silly question (sorry guys I have to do it time is gold right?) but I conclude that maybe he miscalculate his problem or something but it is confirm the answer in a.) is 120 m? I always get 120...

oooops I meant to say 120 m

I borrowed my friend's notebook because I studying about kinematic then I saw this example and resolved it. The answer on a letter A is -72(on his notebook) but I got 120 soooooo I posted in this forum to confirm which is the right answer

Homework Statement A car is stopped at a traffic light. It then travels along a straight road so that its velocity is given by the equation v(t)=(7.20m/s^2)t-(0.720m/s^3)t^2 Determine the following a. The average velocity of the car from t=0s to t=10s b. The instantaneous velocity of the car at...

So about part A, you mean I should multiply by 2 the t? 3.3997 multiply by 2? I thought the t for the ball rises and falls is the same by definition. Right? Okayyy will solve later. I'll update you later for my final sol'n thank you!

So you mean to say -63.7 m = (0)(t)-1/2(9.8)(t)^2 ?? I assume you're pertaining to c.) and also is my a.) and b.) right? just to be clear.

Homework Statement A ball is thrown vertically upward with an initial speed of 19.6 m/s from the top of a building 44.1 m tall. Assuming that there is no air resistance. a.) At what two times is the ball 10.0 m above its starting point? b.) What is the position of the ball at t = 5.00 s? c.)...

typo 8/Vocos50 but it is right the context is still there..

SIR I THINK I GOT IT. Okay here goes ΔX = Vox(t) right? bc a is always 0 ΔX/Vox = t but we know that Vox=VoCos50 and ΔX = 8 so 8/Vocos50 = t Voy=Vosin50 right? So Δy=Voy(t)-1/2g(t)^2 3-2=(Vosin50)(Vocos50)-1/2(9.8)(Vocos50)^2