for b)
i said
E\capO= {f\epsilonv | f(x)= f(-x) and f(x)=-f(-x), \forallx\epsilonR}
E\capO= {f\epsilonv | f(x)= -f(x), \forallx\epsilonR}
E\capO= {f\epsilonv | f(x)= 0, \forallx\epsilonR}
E\capO= {0} (f(x) =0 is the zero function)
what do you think?
Let V be the vector space of all functions from R to R, equipped with the usual
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Let D =
[d11 d12]
[d21 d22]
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