I say, do both bio-medical engineering PhD and medicine. It's worthwhile since both are related and heavily converge, and allows a lot of flexibility career-wise as well.
Both an engineer or scientist could do research or be involved in production. It's just that the engineering model is multidisciplinary and practical, while scientists tend to more theoretical. There is the applied sciences, but tend to be more specialized.
I am enrolled in electrical engineering (and will specialize in bio-medical in 3 semesters). My career that I think I'll be involved in is within the field of medicine. However, I am interested in other fields of engineering especially mechanical.
Having said that, have any engineers here...
Does that mean the term, the observer effect is used? I understand that the phenomena exists, but I haven't seen many academic sources using the term. However I've heard the term used in journals outside QM, though.
I got a question. Is this excerpt from wikipedia correct?
http://en.wikipedia.org/wiki/Observer_effect_(physics )
Does that mean there is no observer effect when acts of observation and measurement are defined in quantum terms?
Does anyone have sources that augment or dispute this...
I got it to work. Seems to work. Just forgot to active l-conio in my compiler and how void functions work.
My problem right now is digit detection. Here is my problem statement:
Problem Statement:
Using the <conio.h> library, use simple text characters to animate a pencil which leaves...
Homework Statement
The program will request the user to enter a name. Once entered, the screen is cleared and it moves onto a new screen. If not, input is requested once again.
char name
Homework Equations
void clrscr()
Possibly if statements
printf ("Please enter your...
So it would be
Fnet = T + Fg = - ma
T + (-mg) = - ma
T - mg = - ma
T = - ma + mg
Correct?
Acceleration of Fnet cannot exceed gravity downwards, because it is the difference between Tension and Fg.
T + Fg = - m1*a ---> T + (-mg) = - m1*a ------> T - mg = - m1*a ----> T = - m1*a +...
One more question. Instead of equating the acceleration of the two equations, I isolated the tension.
m1 = 5.00kg
m2 = 3.00kg
u = coefficient of friction
Block 1
T + Fg = m1*a ---> T + (-mg) = m1*a ------> T - mg = m1*a ----> T = m1*a + mg
Block 2:
T + Ff = m2*a ---> T + (-uN)...
1. Just noticed.
2. Acknowledged.
3. Friction on the sliding block acts in the opposite direction of tension.
4. Tension acts in the opposite direction of gravity.
5. Will do.
Thanks. :)
Homework Statement
A 5.00kg hanging block is connected by a string over a light pulley to a 3.00kg block that is sliding on a flat table. The coefficient of friction between the 3.00kg block and the surface is 0.400. The system starts from rest. What is the speed of the 5.00kg block when it...