Recent content by venceslau

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    Circuit 1 with Resistors and Battery

    Please Help - Circuit 1 with Resistors and Battery Hi, I'd like to revive this thread. I'm solving the exact same problem but with different values. The last question is asking me the following: 6) If the value of the resistor R2 were doubled, how would the value of the resistor R3 have to...
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    Solve 1D Explosion Problem: Find Mass, Speed, Force & Momentum

    Thank you Spinnor, I finally got it! I appreciate your help. Cheers
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    Solve 1D Explosion Problem: Find Mass, Speed, Force & Momentum

    Thank you both for your replies. Spinnor, I agree with you, the wording on that last question is definitely incorrect, thanks for pointing that out. Now, I am not so sure how I would go about using conservation of momentum to find out how the energy would be shared between the different...
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    Solve 1D Explosion Problem: Find Mass, Speed, Force & Momentum

    Homework Statement An object with total mass mtotal = 8.6 kg is sitting at rest when it explodes into two pieces. The two pieces, after the explosion, have masses of m and 3m. During the explosion, the pieces are given a total energy of E = 48.0 J. 1) What is the speed of the smaller piece...
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    What is the acceleration of the block on the incline?

    Doc Al, thanks for your prompt reply! This is an online system, and it only took the answer as being correct once I excluded the Y component of the Tension. But I agree with you, it should be factored in there. All the equations I presented above, have already been accepted by the system...
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    What is the acceleration of the block on the incline?

    Homework Statement A mass m = 16.0 kg is pulled along a horizontal floor, with a coefficient of kinetic friction μk = 0.14, for a distance d = 8.3 m. Then the mass is continued to be pulled up a frictionless incline that makes an angle θ = 38.0° with the horizontal. The entire time the...
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    Work done by gravity by Wonder Woman

    Thanks for pointing that out! Fixed. I am the worst for making dumb mistakes like that. I appreciate your quick reply, I can now finish my homework. :)
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    Work done by gravity by Wonder Woman

    Ohh...I feel so dumb now. lol. So, will it be just the change in potential energy for Δh? So final equation is W=m*g*Δh=m*g*(30-30*cos(θ)) ? So final equation is W=m*g*Δh=m*g*(13-13*cos(θ)) ? Thanks
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    Work done by gravity by Wonder Woman

    Work done against gravity by Wonder Woman Homework Statement Wonder Woman, whose mass is 52 kg, is holding onto the free end of a 13.0 m rope, the other end of which is fixed to a tree limb above. She is able to get the rope in motion so that she can reach a ledge when the rope makes a 60...
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