1.) In a typical fireworks device, the hat of the reaction between the strong oxidizing agent, such as KCLO4, and an organic compound excites certain salts, which emit specific colours. Strontium salts have an intense emission at 631 nm, and barium salts have one at 493 nm.
Part a was simple...
Shoot... I forgot to take into account the sign of cos(180) is a negative... I was getting 0 for (1 - cos(theta))... Stupid simple mistake that I missed until after handing my assignment in.
Pretty easy one, I'd imagine. Just want to check it over.Homework Statement If the maximum energy transferred to an electron during Compton Scattering is 50keV, what is the wavelength of the incident photon?
Homework Equations
lamba = (h*c)/(E)
(lamba' - lambdao) = (h/mc) (1 - cos (theta))...
Very amateurish mistake by me, really... I know the difference, just kind of messed up in the way I was writing it out. Ended up with the inverse of the time rather than time :p
Just a quick check though. I think I edited my reply when you were writing yours. Am I looking for an answer something along the lines of t = (v +- c)/(d) = ([lc]/d +- c)/d = (lc +- cd)/(d^2)?
I guess when you put it like that, it seems rather simple... Perhaps I'm just trying to complicate things more, but I figured this would be an issue of time dilation considering it's a problem we were given in our first chapter of Modern Physics, which deals with time dilation and length...
Yeah, I'm getting that the speed of the train is (lc)/d given the relevant information, I'm just not entirely sure how to factor this into figuring out the time it takes for either lightning bolt to reach observer O'. I'm probably not thinking about this in the correct mindset...
Homework Statement
Two lightning bolts strike the ends of a moving boxcar (Points A and B). The boxcar has length 2d and is moving at a speed v. A stationary observes both lightning bolts hitting the boxcar simultaneously. An observer in the car, however, claims that the front (position B') of...
According to the computer, that's the answer I should be getting... So, yes, 51.1 is the correct answer. I'm just not quite able to get that.
I'm betting I'm just running into one little snag in the process that's messing it up.
Tx = (mv^2)/(sin(theta)r) and Ty=(mg)/(cos(theta))
I can do that, sure, Neutrino. Just not sure what else to do with it from there. I have neither tension, theta, or the radius of the conical base. Only the length of the string, the mass, and the velocity.
http://capaserv.physics.mun.ca/msuphysicslib/Graphics/Gtype11/prob03_pendulum.gif
A mass of 8.700 kg is suspended from a 1.490 m long string. It revolves in a horizontal circle.
The tangential speed of the mass is 3.755 m/s. Calculate the angle between the string and the vertical (in degrees)...