Recent content by vongola13th

Since I know the formula for work W=Fxdcostheta, I wanted to make sure the that about of work would be the same as for the case of the ramp and the case of the box being lifted up 90degrees. I figured that the side length must be 3.92 and used that as they hyp. I used sin to figure out the angle...

okay sorry, I figured out 196J=fxd 196=50*d 3.92=d I now have the opposite and the hyp. I did sin^-1(2/3.92)=30degrees I double checked it with 50*3.92*cos30degrees= 168J This is not the 196 joules needed, where did I go wrong?

Yea I looked at it and do I'm still lost, could you please tell me how to find it

so the force requried to life the first box is 98N, so 98=sin(90) =98 what about the other one, it wouldn't be 50=sintheta right?

Homework Statement A small explosive charge is placed in a rubber block resting on a smoother surface(frictionless). when the charge is detonated, the block breaks into three pieces. A 200g piece travels 1.4 m/s and 300g piece travels at 0.90m/s. The third piece flies off at a speed of...

Homework Statement Two boxes each mass 10 kg are raised 2.0m to a shelf. The first one is lifted and second one is pushed up a smooth ramp(frictionless). If the applied force on the second box is 50N, calculator the angle between the ramp and the ground Homework Equations n/a The...

so it would be 32.4-5.6=26.8 26.8/0.4=67m/s? Is this right?

Homework Statement A force that averages 1200N is applied to a 0.4kg steel ball moving at 14m/s in a collision lasting 27ms. If the force is in a direction opposite the inital velocity of the ball ,find the final speed and direction of the ball Homework Equations n/a The Attempt at...