Calculating Final Speed and Direction of a Moving Object in a Collision

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Homework Help Overview

The problem involves calculating the final speed and direction of a steel ball after a collision, given a force applied in the opposite direction of its initial velocity. The subject area pertains to dynamics and impulse-momentum principles.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the application of impulse-momentum concepts, with attempts to calculate the final velocity using the impulse equation. Questions arise regarding the sign of the initial velocity and the interpretation of the force direction.

Discussion Status

Multiple interpretations of the calculations are being explored, with some participants questioning the correctness of the initial assumptions and calculations. There is a mix of agreement and uncertainty regarding the final results presented.

Contextual Notes

Participants are navigating the implications of the force direction and the definitions of initial and final velocities. The discussion reflects a lack of consensus on the correct approach and results, highlighting the complexity of the problem.

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Homework Statement


A force that averages 1200N is applied to a 0.4kg steel ball moving at 14m/s in a collision lasting 27ms. If the force is in a direction
opposite the inital velocity of the ball ,find the final speed and direction of the ball


Homework Equations



n/a

The Attempt at a Solution


I used FdeltaT=mv
1200(27x10^-3)=0.4(v2-v1)
32.4=0.4v2-5.6
38/0.4=v2
95m/s =V2. Is this correct?
 
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Fdt = Δp is a vector equation.
You have defined the impulse FΔt as positive, so v1 is negative.
 
rude man said:
Fdt = Δp is a vector equation.
You have defined the impulse FΔt as positive, so v1 is negative.

so it would be 32.4-5.6=26.8
26.8/0.4=67m/s?
Is this right?
 
vongola13th said:
so it would be 32.4-5.6=26.8
26.8/0.4=67m/s?
Is this right?

Yes it is.
 

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