I don't have cross-sectional area. How else can I go about getting the pressure... between surface and the depth given? I assume the initial pressure goes something along the lines of 9.81x291 (g*h).
I guess my real question is: does the depth of the water make any difference or do i assume it's constant pressure? If i can't make that assumption, how do i calculate the pressure the water has on this?
The obvious answer is that if it's to the nearest tenth of a cm3, it's still coming out...
I have absolutely no idea how to do this question. I've tried several different ways.. tried using the equation:
P = (1/3)*(N/V)*2*((3/2)kT)
Then using the idea that:
P = F/A
No luck. I think I'm doing things wrong. Does this have something to do with internal energy? (U = (3/2)nRT)
Two identical objects are placed in a room at 26°C. Object 1 has a temperature of 81°C and object 2 has a temperature of 35°C. What is the ratio of the net power emitted by object 1 to that radiated by object 2?
Answer is supposed to be (power emitted by 1 / power emitted by 2)
I've tried...
The answer that the book gives for the question:
What is the launch speed of a projectile that rises above the Earth to an altitude equal to the Earth's radius? Ans. 7.91 km/s
Now I have the question:
What is the launch speed of a projectile that rises above the Earth to an altitude equal...
Here's a site I found with the same problem. You can view the correct answers and try to work to it, but I still haven't figured out the proper equation yet.
http://wps.prenhall.com/wps/media/objects/1088/1114211/ch8/Chapter_8.html
Yeah.. that equation isn't working for me. Why (L-1), btw? And mass of the ball.. are you dividing the N value by 9.81 or did you mean the force of the ball (in N)?
So I've been using:
\alpha=\tau/I
More specifically:
\alpha=(r*F)/(.5mr^2)
I know I'm getting the acceleration just fine. I've then been using:
\omega^2 = 2\alpha\Delta\Theta
I know the problem is coming in here. Probably in conversion of units (rad/s^2) to (rev/s^2) or something...
Been trying this one using:
x1m1 = x2m2
I guess I just maybe am not using the right mass or length for center of mass..
Here's the question:
A 0.19 kg meter stick balances at its center. If a necklace is suspended from one end of the stick, the balance point moves 16.3 cm toward that...