Ya, Norman. I do need to incorporate fringe benefits as well. If you happen to have your proposals easily at hand then that would be great. If not, don't worry about it.
The PhD is not necessarily in physics. In this particular case, we have a Biochemist, a Physicist, and a Materials...
So I have to put together a mock budget for a funding proposal. I am unsure, however, how much I need to pay the research assistants I will have working on the project. I also don't have a good idea of how much a professional with a PhD or master's would be paid to work on a project.
This summer I am looking to get involved in research at my university. I am eager to go and meet with a professor to see if I can hold a position for him, but I am very intimidated and I sometimes feel like I don't know enough to contribute to a research team. I have been told...
Okay, so I think I figured out my problem. I was doing something wrong with the component form.
Here is what I got for my inertia tensor:
I_11 = 0
I_22 = (1/3)ml^2
I_33 = (1/3)ml^2
I_12 = I_21 = 0
I_13 = I_31 = 0
I_23 = I_32 = 0
So it looks something like this...
A thin rod has mass M and length L. What is the moment of inertia tensor about the center of mass if placed along the x axis.
I would write the inertia tensor in component notation, but I don't know how to use Latex.
The Attempt at a Solution...
I don't think it's an algebraic error. I have worked the problem through, once using endpoints x=0 and x=L and again using x=-L/2 and x=L/2 and I don't get the same answer.
In the case where I am going from 0 to L, I get that the energy is E=(n^2*h^2)/8mL^2, which is correct.
In the case...
Find the energy of a particle of mass m in an infinite square well with one end at x=-L/2 and the other at x=L/2.
The Attempt at a Solution
To save time, I won't type the solving of the differential equation which results...
One particle is shot in the x direction at speed u and a second is shot in the y direction at speed u as well. Show that the relative speed of one to the other is: u(2-(u/c)^2)^1/2.
velocity addition: u = (u' +/- v)/(1 +/- u'*v)