How do I figure out net force?
The experiment is a cart with weights with a string attatched to it, the string dangles over a pulley that is attatched to a flat desk and the weights on the end of the string use the force of gravity to pull the cart forward until the weight on the end of the...
The question is:
Plot a graph of the acceleration (vertical axis) as a function of the net force for the trials in which the mass remained constant. Draw a line of best fit and calculate its slope. What does the graph indicate about the relationship betweena cceleration and net force?
What...
Ok so I'm going to do:
t = (V2 - V1) / a
= (2.4 - 0) / 9.8
= 2.4 / 9.8
= 0.244897959
Since that is only how long it takes for it to go up to its max height, it must be multiplied by two.
0.489795918
Ok then I add that onto how long it takes to fall from 3.6 metres.
0.489... +...
Ok I think I'm stuck on the second part now.
I have calculated that it will take 0.857142857 seconds for a ball to travel if it were to be just dropped from 3.6 m above ground. I don't even know what equation I should use now to find out at what time I should drop the ball at. I think I have...
In this case + = down
V2^2 = (2.8)^2 + 2(9.8)(3.6)
= 7.84 + 70.56
= 78.4
V2 = sqrt(78.4)
V2 = 8.8543...
Therefore the speed of the ball as it hits the ground is 8.9 m/s.Sorry for bad form.
V2^2 = V1^2 + 2*a*dV2 = Final speed
V1 = Initial speed
The thing I'm having a problem with is if you say that + = up... That makes it so you have to find a square root of a negative number which you can't do. The only way it works is if 3.6 becomes negative too but I don't think distances can...
Heres question I need help with. I'm in Grade 11 Physics.
A ball is thrown vertically upward from a window that is 3.6 m above the ground. The ball's initial speed is 2.8 m/s and the acceleration due to gravity is 9.8 m/s^2.
a) What is the ball's speed when it hits the ground?
b) How long...
Sorry, I meant to write the question like a fraction I just didn't know the code. When you are simplifying roots, and you take out let's say the root of 4, do you times the number already outside the root sign by 2?
\frac{5\sqrt{24}}{2\sqrt{18}}
=\frac{5\sqrt{4*6}}{2\sqrt{3*6}} (don't...
I feel embarassed to ask these questions but what is the rule for to simplify division, addition, and subtraction square roots? Here are some questions:
SIMPLIFY:5\sqrt{24}\div2\sqrt{18}
\sqrt{40} + \sqrt{90}
\sqrt{50} - \sqrt{18}
Yes, I think I got it now. I had them figured out all along I just found the question wordy and didn't know where to go from next. I think I have it now, you get the midpoints, connect the dots with lines (in my head) and figure the perimeter of the new object.