Recent content by wbrigg

off to reading eh. If by "angle between each pair of vectors" you mean each vector and it's nearest neighbor, then it would only work for a 2D space (or 2D plane in higher dimensions). i.e. you could just arrange the points around an equator of the sphere and it would satisfy your...

i'm looking for a way to distribute n points so that they cover all directions evenly if you draw a line from the origin to each point. In 3 dimensions this corresponds to evenly spacing points around a sphere, and in two dimensions around a circle. In one dimension it's just left and right (or...

have i put this in the wrong thread/forum thing?

yeah, that's what i was thinking. it just seemed too easy! so \vec{\mu} = \frac{q \omega r^{2}}{2}

Homework Statement "A particle of charge q is rotating in a circular orbit of radius r[/i with angular velocity [i]w. Determine the magnetic moment associated with the motion of the charge. Homework Equations Q=IT? \vec{\mu}=I\vec{A} The Attempt at a Solution I know how to do it...

thanks.

Yeah, i meant replace the i with a q/dq - which is what you said. never used latex before, so it's kinda hard to skim through it and check everything's correct. and it probably would be easier just to have integrated the field twice.

oh, yeah. 0 squared is zero.

hey all, I was wandering if there was a way to spread vectors as evenly as possible through space (all originating from the same point. In 2D, this is easy, i just divide a unit circle into the number of peices i require (or in the specific case I'm looking at it for, i divide the 1st...

no. An interpretation of the square of the wavefunction is the probability of finding it somewhere; i.e.\int^{a}_{b}|\Psi(x,t)|^{2}dx is the probability of finding the particle between a and b. you're looking at the probability of finding the particle inbetween +/-\infty. I.e. anywhere.

the biggest problem I'm having looking at the possible answers is that none of them contain y, they should be of the form u=xCos\theta +ySin\theta + a sure, the question says with respect to x, but there's a constant at the end, you can't just ignore the y components...

from reading the question it looks like there should be a diagram included...

can you write out the question exactly as it's worded?

e^{i\theta} = Cos\theta + iSin\theta That should help signifigantly.and about the Latex thing, click the "go advanced" tab when you reply to a message, of start a new thread or topic / whatever, and click the button that has a Sigma on it. it should be the last one on the bottom row on the right.

hey, i have a question from an exam paper which isn't worded too nicely (most of the questions on the exam are worded in similar ways ) The way I've done it is to first put in my first shell of infintesimal charge and then treat it as a point charge. Then i treat the next shell as just a point...