Recent content by wglmb
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Graduate Confused about Euler-Lagrange Equations and Partial Differentiation
oops, haha good point. Thanks.- wglmb
- Post #7
- Forum: Special and General Relativity
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Graduate Confused about Euler-Lagrange Equations and Partial Differentiation
Well this is it - I don't know what should be considered a function of s. If it's just z-dot then \frac{2R^2}{z^2}\ddot{z} If it's z-dot & z then \frac{2R^2}{z^2}\ddot{z} - \frac{4R^2}{z^3}\dot{z}^2- wglmb
- Post #5
- Forum: Special and General Relativity
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Graduate Confused about Euler-Lagrange Equations and Partial Differentiation
\frac{2R^2}{z^2}\dot{z}- wglmb
- Post #3
- Forum: Special and General Relativity
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Graduate Confused about Euler-Lagrange Equations and Partial Differentiation
I have a Lagrangian L = \frac{R^2}{z^2} ( -\dot{t}^2 +\dot{x}^2 +\dot{y}^2 +\dot{z}^2) and I want to find the Euler-Lagrange equations \frac{\partial L}{\partial q} = \frac{d}{ds} \frac{\partial L}{\partial \dot{q}} I'm fine with the LHS and the partial differentiation on the RHS, but when it...- wglmb
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- Confusion Euler-lagrange
- Replies: 6
- Forum: Special and General Relativity
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Graduate Is a Curve Timelike, Spacelike, or Null?
awesome, thanks!- wglmb
- Post #3
- Forum: Special and General Relativity
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Graduate Is a Curve Timelike, Spacelike, or Null?
If I have a line element ds^{2} = ... and a curve defined by x^{1} = f( \lambda ), x^{2} = g( \lambda ) etc, and I wand to know if the curve is timelike, spacelike, or null, do I do so by checking the sign of g_{\mu \nu} \frac{dx^{\mu}}{d\lambda} \frac{dx^{\nu}}{d\lambda} ?- wglmb
- Thread
- Replies: 2
- Forum: Special and General Relativity
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What is the signature of the given metric?
Thanks for your help - I think I've got it. As x \rightarrow \infty the signature is 0 As x \rightarrow 0 the signature is 1 So this implies that the metric is not well defined for all 0<\infty, since the signature should be constant.- wglmb
- Post #8
- Forum: Advanced Physics Homework Help
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What is the signature of the given metric?
Ah, I think I see! (I hope) You mean that, since the signature is constant, I can take any x,y,t that I like and calculate it for them?- wglmb
- Post #7
- Forum: Advanced Physics Homework Help
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What is the signature of the given metric?
uh, sorry, I can't see what you're getting at... are you saying I don't need to find the eigenvalues at all?- wglmb
- Post #5
- Forum: Advanced Physics Homework Help
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What is the signature of the given metric?
No, but a later question is "Is the metric well-defined for all 0<x<\infty?" Haven't though about it, but I assume the answer is no, and that suitable restrictions will make it OK. yeeees, but how do I find it? The wikipedia way is to diagonalise the matrix (by finding eigenvalues, then...- wglmb
- Post #3
- Forum: Advanced Physics Homework Help
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What is the signature of the given metric?
Homework Statement I have a metric and I need to find the signature. Homework Equations ds^{2} = -(1-e^{-x^{2}})\ dt^{2} + 6x\ dy^{2} + 9\ dx\ dy + y^{2}\ dx^{2} The Attempt at a Solution In matrix form, the metric is \begin{pmatrix} -(1-e^{-x^{2}}) & 0 & 0 \\ 0 & y^{2} & 9 \\ 0 & 9 & 6x...- wglmb
- Thread
- Metric
- Replies: 7
- Forum: Advanced Physics Homework Help
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Prove continuouty of 1/x (delta-epsilon)
Hi guys, I've been trying to do this for a while but I'm not really getting anywhere. Hints would be much appreciated! Homework Statement Prove that the function g(x)=1/x is continuous on \latexbb{R}\smallsetminus\{0\}, but cannot be defined at the origin 0 in such a way that the...- wglmb
- Thread
- Replies: 1
- Forum: Calculus and Beyond Homework Help
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Lagrangian mechanics for two springs
It's OK, I've figured it out now. Thanks :)- wglmb
- Post #6
- Forum: Advanced Physics Homework Help
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Lagrangian mechanics for two springs
Ah, I see what you mean - of course! I don't have time just now but I'll work that through later and see how I manage :) Edit: Hmm, well I still get the same matrices A and B, since they come from the double-dotted terms and the x&y terms. The constant terms (now -mg for both of the equations...- wglmb
- Post #5
- Forum: Advanced Physics Homework Help
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Lagrangian mechanics for two springs
Haven't I got that included in the mg(3l+x+y) part of the PE? This comes from mg(l+x)+mg(2l+y) which is mg times the height of the first particle plus mg times the height of the second.- wglmb
- Post #3
- Forum: Advanced Physics Homework Help