# Recent content by Whotto

1. ### Torque - Where is the normal force in this FBD?

Ah! I get it now. Thank you very much :)
2. ### Torque - Where is the normal force in this FBD?

My apologies...I forgot to include that 0.70m of the stick is in contact with the table. Sorry! I am not missing any other information though, I double-checked to make sure.
3. ### Torque - Where is the normal force in this FBD?

Okay, I after further pondering, I realized that FN could range from mg to 0. So that means the bug could only have as much torque as mg. So the answer would be 0.16m. Am I right or still totally wrong?
4. ### Torque - Where is the normal force in this FBD?

Hi MHrtz, thanks for the reply. Do you mean this then? [PLAIN]http://img153.imageshack.us/img153/2333/95048564.jpg [Broken] I can't solve the question if it is this, because any weight on the right side will tip the ruler - which isn't suppose to happen.
5. ### Torque - Where is the normal force in this FBD?

Silly question I know, but I want to just clarify this. The actual question: A 0.45kg bug is crawling to the right along a metre-stick which is resting on the edge of a desk. If the mass of the uniform metre-stick is 0.37kg, how far from the edge of the desk can the bug crawl before the...
6. ### Equilibrium of a hanging mass

I got the answer now. I have thought about why we would change the axis for the inclined planes, but that is due to the fact we knew the Normal force is perpendicular to the surface. The confusion that I had with this problem is that there is no indication that the angle between the string...
7. ### Equilibrium of a hanging mass

All right, seems fairly odd to me that they would go against what teachers have taught. Thanks!
8. ### Equilibrium of a hanging mass

Thanks for your reply! But the diagram does not tell me the angle is 90. Wouldn't that mean I cannot assume it is 90?
9. ### Equilibrium of a hanging mass

Homework Statement A mass suspended by a string is held 24o from vertical by a force of 13.8N as shown. Find the mass. http://img525.imageshack.us/img525/3421/problem32.jpg [Broken] 2. The attempt at a solution [PLAIN][PLAIN]http://img205.imageshack.us/img205/6100/attemptv.jpg [Broken]...
10. ### Projectile Motion Problem - Diving

Ah, I get it now! Much appreciated and thank you for taking the time, rockfreak, collinsmark, and bhat! and yes - I will definitely keep better track of my signs.
11. ### Projectile Motion Problem - Diving

Hi Collinsmark, It is much clearer to me now. I got 0.474 seconds with -4m/s instead. So the equation 0 = \frac {1}{2}at^{2} + v_{0}t - d would include the height that the diver has gained while taken off, even though d = 3m anyways? Thank you for the good explanation! Thanks for the...
12. ### Projectile Motion Problem - Diving

I get what you've said so far, but I don't understand how it works into my problem. I will try ask my question in another way: Previous: http://img638.imageshack.us/img638/1486/diagram2b.jpg [Broken] New situation: [PLAIN][PLAIN]http://img205.imageshack.us/img205/1645/diagram3.jpg [Broken]...
13. ### Projectile Motion Problem - Diving

Thanks for the quick reply rock freak! So then d = displacement I take it. If the diving board was right on top of the water then d = 0?
14. ### Projectile Motion Problem - Diving

This is a projectile motion problem at a Grade 12 level in Canada. My main problem here is conceptual, not the math itself. 1. The given question A diver takes off with a speed of 8.0m/s from a 3.0-m high diving board at 30o above the horizontal. How much later does she strike the water? My...
15. ### Satellites in Circular Orbits

Thanks! I got #2 with the formula T = ( 2 pi r3/2 ) / sqrt(GMe). But I still don't get #1. Can I get some more pointers?