How do you solve for the mass of a hanging object with two given forces?

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Homework Help Overview

The problem involves determining the mass of a hanging object that is subjected to two forces, one of which is at an angle from the vertical. The original poster presents equations derived from resolving forces along different axes but expresses uncertainty about the angle and its implications for the solution.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • The original poster attempts to resolve forces into components and formulates equations based on these components. Some participants suggest that the angle between the forces may not be necessary for solving the problem, while others question the validity of assuming a right angle without explicit information.

Discussion Status

The discussion includes attempts to clarify the assumptions regarding the angles involved and the coordinate system used. Some participants provide guidance on how to approach the problem differently, and the original poster reflects on their understanding of the coordinate system after receiving feedback.

Contextual Notes

The original poster indicates a potential lack of information regarding the angles involved in the problem setup, which may affect their ability to solve for the mass accurately.

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Homework Statement



A mass suspended by a string is held 24o from vertical by a force of 13.8N as shown. Find the mass.

[PLAIN]http://img525.imageshack.us/img525/3421/problem32.jpg

2. The attempt at a solution

[PLAIN]http://img205.imageshack.us/img205/6100/attemptv.jpg

I've split it up the two given forces (F, and FT) by their axis and got the two equations:

1. 13.8N Sin\ominus + F_{T}Cos24 = mg2. 13.8N Cos\ominus = F_{T}Sin24

Continuing on to solving for FT with equation two, I get

3. F_{T} = \frac{Sin24}{13.8N Cos\ominus}

I plug equation 3 into 1 to get

13.8N Sin\ominus + \frac{Sin24}{13.8N Cos\ominus}Cos24 = mg

and solving for m to get:

\frac{13.8N Sin\ominus 13.8N Cos\ominus + Sin24Cos24}{9.8m/s^{2}} = m

3. Where I'm stuck

I can't get theta to solve for m. I have tried to get it through geometry and any other ways I could think of. Am I missing information in order to solve this problem, or am I just not doing this correctly?

Any help would be appreciated. Many thanks!
 
Last edited by a moderator:
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Resolve Forces in tangential direction and equate them no need of the angle you assumed.
Take coordinate axis as y=tension x=F this solution is possible if angle between F and Tension is 90
 
Aditya Tarey said:
Resolve Forces in tangential direction and equate them no need of the angle you assumed.
Take coordinate axis as y=tension x=F this solution is possible if angle between F and Tension is 90

Thanks for your reply!

But the diagram does not tell me the angle is 90. Wouldn't that mean I cannot assume it is 90?
 
otherwise angle should be given. Always take coordinate axis in such a way that variables in question are reduced this is the concept to minimize the time you take for problem solving.
 
All right, seems fairly odd to me that they would go against what teachers have taught.

Thanks!
 
You must have seen problems on projectile motion on an incline . What coordinate axis did you choose?
 
I got the answer now.

I have thought about why we would change the axis for the inclined planes, but that is due to the fact we knew the Normal force is perpendicular to the surface. The confusion that I had with this problem is that there is no indication that the angle between the string and force is 90 degrees.

But once I changed the axis to make the string perpendicular to the x axis, I got the right answer.

Nevermind me, I'm too picky.

Your help has been much appreciated Aditya Tarey!
 

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