\frac{d}{dV} is the derivative with respect to the function V(t).
This is a calculus of variations problem, and the functional is
\int_0^{t_1}{\mathcal{M}}dt,
\mathcal{M} = \int_0^t{V(\tau)}d\tau + \text{other stuff...}
What I'm trying to do, is find the equation for...
Thinking more about the problem, if it is legal to bring the derivative inside the integral, then the answer would just be t. This seems odd in the context of the larger problem, though.
Can anybody comment on if this is correct or not. Thanks.
Homework Statement
I'm trying to take the derivative of the following integral
\frac{d}{d V} \int_0^t{V(\tau)}d\tau
Homework Equations
FTC will probably be a part of it.
The Attempt at a Solution
I always get confused when I'm taking the derivative of an integral. I know the answer is...
Homework Statement
As part of a larger problem, I'm trying to understand the dynamic equations of the attached circuit with two capacitors and one resistor and a voltage source. When I use Kirchoff's Current Law at nodes V0 and V1, I get the following equations.
Homework Equations
See...
Hello,
As part of a larger problem, I'm trying to understand the dynamic equations of the attached circuit with two capacitors and one resistor and a voltage source. When I use Kirchoff's Current Law at nodes V0 and V1, I get the following equations.
0 = (dVs/dt-dV1/dt)*C1 - (V1-V2)/R -...