Recent content by wilsondd

\frac{d}{dV} is the derivative with respect to the function V(t). This is a calculus of variations problem, and the functional is \int_0^{t_1}{\mathcal{M}}dt, \mathcal{M} = \int_0^t{V(\tau)}d\tau + \text{other stuff...} What I'm trying to do, is find the equation for...

Thinking more about the problem, if it is legal to bring the derivative inside the integral, then the answer would just be t. This seems odd in the context of the larger problem, though. Can anybody comment on if this is correct or not. Thanks.

Yes, I agree it is weird, but it is part of a calculus of variations problem, and is not a typo or anything.

Homework Statement I'm trying to take the derivative of the following integral \frac{d}{d V} \int_0^t{V(\tau)}d\tau Homework Equations FTC will probably be a part of it. The Attempt at a Solution I always get confused when I'm taking the derivative of an integral. I know the answer is...

Yes, but what if the voltage source is not constant?

Homework Statement As part of a larger problem, I'm trying to understand the dynamic equations of the attached circuit with two capacitors and one resistor and a voltage source. When I use Kirchoff's Current Law at nodes V0 and V1, I get the following equations. Homework Equations See...

Hello, As part of a larger problem, I'm trying to understand the dynamic equations of the attached circuit with two capacitors and one resistor and a voltage source. When I use Kirchoff's Current Law at nodes V0 and V1, I get the following equations. 0 = (dVs/dt-dV1/dt)*C1 - (V1-V2)/R -...