Recent content by Wisal

But is not the 'y'(vertical displacement) always constant as the displacement will always be 3 no matter what? I mean the final displacement will be 3. Thanks for the help :D

y = xtanθ - (gx^2 secθ^2)/2 Comment: as we take g =- 9.81 so negative sign) 2y = 2xtanθ-gx^2secθ^2 2y = 2xtanθ-gx^2-gx^2(tanθ)^2 2y+gx^2=2xtanθ-gx^2(tanθ)^2 now plugging in the values: x = 20; y =3 2(3) +(9.81*400)=2(20)tanθ-(9.81*400)(tanθ)^2 now by substituting any variable say 'x' as tanθ...

And also could you tell me the intuitive reason why we took g as -9.81( I am sometimes confused by this). I do get why we took this value in this particular problem as we had to get a maximum value of tanθ hence we get a parabola with a maximum point. And, am I right in thinking that there will...

Okay, that's what I have reached at: is the answer 89.7 degrees?

I have already done that: I formulated two equations: 1. vCosθ * t = 20 as x =20 2. 3 = vSinθ(t) + g(t^2)/2 as y =3 and then substituting the value of 't' i.e. 20/vcosθ in the second equation

well the problem, unfortunately, in front of me only gives this information. I think that there will be different minimum velocity for every possible angle. Am I right? and how do we find the range of angles possible?

Oh yes! How stupid of me to ask :P But how will we find the lowest value of v?

But won't there be an optimal solution to this, the solution that takes the least time? I mean the value of v that takes the least time?

Well, intuitively speaking, I think that this problem will have a range of values as we can hit the apple along a variety of trajectories.

Homework Statement In the Fig. What should be the initial velocity (magnitude and direction) of the arrow? Also calculate the time of flight. Homework EquationsThe Attempt at a Solution I have formulated 2 equations: v*cos(theta) * t = 20 and 3 = (v * Sin(theta) * t) + (9.81 * t^2)/2 when...