Ok so:
v0 = 3/2*vR
vR = 2/3*v0
But I don't think I can go on any further because I haven't actually been given any values for μk, v0 or R
So the closest I can come is:
t = v0/(3*μkg)
t = v0/(29.4*μk)
So that would make something like:
Δp = Mv0 - MvR = -fkt
and
Δp = Icmω = fkRt
so
vR = v0 - μkgt
and
ω = (2μkgt)/R
so
vR = 2μkgt = v0 - μkgt
v0 = 3μkgt
I always seem to have too any unknowns left over
Homework Statement
A solid homogeneous cylinder of mass M and radius R is moving on a surface with a coefficient of kinetic friction μk. At t=0 the motion f the cylinder is purely translational with a velocity v0 that is parallel to the surface and perpendicular to the central axis of the...
Thanks for the welcome.
I was trying to understand it in terms of kinetic energy and work done by the friction as it rolls.
Using the forces on the cylinder instead makes more sense.
Also, a slightly related question.
Would the vcm of a rolling cylinder with slipping be the same as the...
If I push a cylinder along a surface with friction then am I right in saying that it would almost instantly start a pure rolling motion with a combination of translational and rotational kinetic energy?
Or would it start initially with pure translational motion and gradually accelerate...