Recent content by Wumbolog

I can't figure this out, please help. I need a worked example I can refer to

I put what I meant, which is 2(1+...+n)

So then I have 1+2+3+4+5+(2n-1)+2n But when I subtract the sum of 2n which is 2(1+...+n) the second line is 1+2+3+4+5+2n-2(1+...+n), the odd number (2n-1) somehow disappeared and the number I am supposed to add to get zero -2(1+...+n) is still there I don't understand

I add even numbers

You get n amount of n+1? I am sorry I still don't get it

Hi, I've enclosed my problem and attempt at solution below. I had problems with the latex so I photographed a picture of my work. The first top half is my attempt at the solution and the bottom is the solution that Spivak provides. I don't understand how he reached his solution and I don't...

Thanks guys I finally got it. And the denominator should have been L-N, my mistake.

##V=C-\frac{C-S}{L}N## ##LV=LC-C-SN## ##\frac{LV}{C}=L-SN## ##C=\frac {L-SN}{LV}## but apparently this is wrong... the book gives ##C=\frac{LV-SN}{L-S}##

##V=C-\frac{C-S}{L}N## Solve for C I am extremely frustrated and have made countless attempts at this. I would really appreciate a step by step on this. Thanks.

Nevermind all, this is a stupid, poorly stated question. I apologize

Yes, I meant accelerating, I apologize. I "made" this problem to see what I could do given the acceleration

Its acceleration is 40 m/s^2 at t=1 and its moving to the right.

A fkdkdkel