Recent content by xbebegirlx

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    Solving Ratio & Proportion | Nitrogen, Phosphorus, Potassium Removal

    ok here I got 100bu/90lb=135bu/xlb then I cross multiply 90*135 = 12150/100 = 121.5lb please advise me see if this is right thanks
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    Solving Ratio & Proportion | Nitrogen, Phosphorus, Potassium Removal

    I am still confuse don't know how to start, the bu and lb are same thing?
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    Solving Ratio & Proportion | Nitrogen, Phosphorus, Potassium Removal

    If 100 bu of corn per acre remove 90lb of nitrogen, phosphorus, and potassium (N, P, and K, respectively), how many pounds of N, P, and K are removed by the yield of 135u per acre? I try to figure out how to starting to solve this problem but don't know how some help please
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    Calculating Stopping Distance: Train vs. Cat on Track at 18m/s

    change KE =WF ke=1/2mv 1/2*25000kg*18m/s^2 =75000x d = 54M no conduction don't have enough time to stoo I hope this one right...because if not then I am stuck
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    Finding velocity use energy conservation help

    A .145kg drop from sixth story building window. If each story is 2.5m tall, use energy conservation to find the rock velocity when it strikes the ground. (ignore air resistance) I have: mass .145kg h 2.5m each story 2.5m * 6 = 15m (total height) gravity 9.8ms^2 V=? I am confuse, what...
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    Calculating Stopping Distance: Train vs. Cat on Track at 18m/s

    I have the Mass=25000kg friction force = 75000n time 18m/s I don't know where the 45m fit in I was confuse, to get stopping distance don't I need the coefficient of friction between the train and the rail? usually it giving but in this problem it not I think I need to use this equation...
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    Calculating Stopping Distance: Train vs. Cat on Track at 18m/s

    a 25000kg train travel down a track at 18m/s. a cat wander onto the track 45m ahead of train, causing the conductor to slam on the brakes. The train skids to a stop. If the brakes can provide 75,000 Newtons of friction, will the conductor have enough stopping distance to avoid hitting the cat?
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    Stopping Distance for 25000kg Train Traveling at 18m/s: Conductor's Dilemma

    a 25000kg train travel down a track at 18m/s. a cat wander onto the track 45m ahead of train, causing the conductor to slam on the brakes. The train skids to a stop. If the brakes can provide 75,000 Newtons of friction, will the conductor have enough stopping distance to avoid hitting the cat?
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