Recent content by xbebegirlx

thanks got it

ok here I got 100bu/90lb=135bu/xlb then I cross multiply 90*135 = 12150/100 = 121.5lb please advise me see if this is right thanks

I am still confuse don't know how to start, the bu and lb are same thing?

thanks

If 100 bu of corn per acre remove 90lb of nitrogen, phosphorus, and potassium (N, P, and K, respectively), how many pounds of N, P, and K are removed by the yield of 135u per acre? I try to figure out how to starting to solve this problem but don't know how some help please

change KE =WF ke=1/2mv 1/2*25000kg*18m/s^2 =75000x d = 54M no conduction don't have enough time to stoo I hope this one right...because if not then I am stuck

A .145kg drop from sixth story building window. If each story is 2.5m tall, use energy conservation to find the rock velocity when it strikes the ground. (ignore air resistance) I have: mass .145kg h 2.5m each story 2.5m * 6 = 15m (total height) gravity 9.8ms^2 V=? I am confuse, what...

I have the Mass=25000kg friction force = 75000n time 18m/s I don't know where the 45m fit in I was confuse, to get stopping distance don't I need the coefficient of friction between the train and the rail? usually it giving but in this problem it not I think I need to use this equation...

a 25000kg train travel down a track at 18m/s. a cat wander onto the track 45m ahead of train, causing the conductor to slam on the brakes. The train skids to a stop. If the brakes can provide 75,000 Newtons of friction, will the conductor have enough stopping distance to avoid hitting the cat?

a 25000kg train travel down a track at 18m/s. a cat wander onto the track 45m ahead of train, causing the conductor to slam on the brakes. The train skids to a stop. If the brakes can provide 75,000 Newtons of friction, will the conductor have enough stopping distance to avoid hitting the cat?