Recent content by xupe33jrm
-
X
Projectile Motion: Maximum Height & Velocity Components
Homework Statement A projectile is fired across a horizontal flat plane. Its initial velocity is 25.5 m/s and is fired at an angle of 31.8° above the horizontal (a) How long does it take to get to the maximum height? (b) What is the maximum height? (c) Determine the horizontal and...- xupe33jrm
- Thread
- Components Height Maximum Maximum height Motion Projectile Projectile motion Velocity
- Replies: 1
- Forum: Introductory Physics Homework Help
-
X
What Are the Components of These Two Vectors?
Homework Statement Vector A is 3.28 m long and points along the x axis. Vector B is 190.6 cm long and points at +25° to the positive x axis (a) What are the components of Vector A? (b) What are the components of Vector B? (c) What is the resultant of these two vectors in terms of...- xupe33jrm
- Thread
- Components Components of vectors Vectors
- Replies: 1
- Forum: Introductory Physics Homework Help
-
X
Calculating Work, Speed & Power of a Car Climbing a Hill
I am spinning in circles. What am I missing?- xupe33jrm
- Post #5
- Forum: Introductory Physics Homework Help
-
X
Calculating Work, Speed & Power of a Car Climbing a Hill
On A I tried to use the Work equation W=KE(final)-KE(initial), with KE(f) = .5mv^2(f) and initial being same but using initial velocity. How do I find V final?- xupe33jrm
- Post #3
- Forum: Introductory Physics Homework Help
-
X
Calculating Work, Speed & Power of a Car Climbing a Hill
1. A car of mass 1100 kg starts from rest at sea level and climbs a hill of altitude 50 m. At the top of the hill the car has a speed of 25 m/s. From the top of the hill the driver turns off the engine and coasts down to an altitude of 15 m. Assume the friction and the air resistance to be...- xupe33jrm
- Thread
- Car Hill Power Speed Work
- Replies: 6
- Forum: Introductory Physics Homework Help
-
X
Kinematics - Car accelerating from traffic light
ok so this is what I got for part a: 8x1 = 16x2, so x1 = 2x2, so 2x2 + x2 = 300, which is x2 = 100, so x1=200 then plug x1 into vmax equation which gives u 40m/s. For part B. do I use the equation x=.5at^2 + volt, and do this for both x1 and x2 and then add the times together?- xupe33jrm
- Post #6
- Forum: Introductory Physics Homework Help
-
X
Kinematics - Car accelerating from traffic light
so confused right now. Vmax^2=0^2+2a1s1 which would be Vmax^2 = 2(4)s1 = 8s1 Then: 0 = Vmax^2 + 2(a2s2) which would be Vmax^2 = -2(-8)s2 = 16s2 am I on the right track so far or am I just screwing this up. I am studying for a test and just do not get this problem- xupe33jrm
- Post #4
- Forum: Introductory Physics Homework Help
-
X
Kinematics - Car accelerating from traffic light
Homework Statement The spacing between two traffic lights is 300m. A car can accelerate from rest with a constant acceleration of 4 m/s2 and decelerate at 8 m/s2. (Ignore the reaction time of the deriver.) a) What is the maximum speed the car can reach and still be able to stop right at...- xupe33jrm
- Thread
- Car Kinematics Light
- Replies: 6
- Forum: Introductory Physics Homework Help
-
X
What is the Maximum Horizontal Distance for a Rooftop Escape?
It was my math, thanks! I could not figure out what I was doing wrong!- xupe33jrm
- Post #3
- Forum: Introductory Physics Homework Help
-
X
What is the Maximum Horizontal Distance for a Rooftop Escape?
Homework Statement A criminal is escaping across a rooftop and runs off the roof horizontally at a speed of 5.7 m/s, hoping to land on the roof of an adjacent building. Air resistance is negligible. The horizontal distance between the two buildings is D, and the roof of the adjacent building...- xupe33jrm
- Thread
- Maximum Value
- Replies: 2
- Forum: Introductory Physics Homework Help
-
X
Graphical method to find magnitude and direction
I got the answer, thanks so much guys. I was getting very angry with this problem, but know it seems so easy!- xupe33jrm
- Post #8
- Forum: Introductory Physics Homework Help
-
X
Graphical method to find magnitude and direction
Why would 90 not be on the east horizontal since it points due east? Also when trying to find the answer what equation do I use. I am really confused and I know it is probably a simple problem. Is the drawing I included look right and if so am I trying to find the green side?- xupe33jrm
- Post #6
- Forum: Introductory Physics Homework Help
-
X
Graphical method to find magnitude and direction
Could someone maybe draw me a diagram on how to set it up, because I am just not understanding. This problem is driving me nuts. If I knew how to draw it maybe I can figure out the math! thanks!- xupe33jrm
- Post #4
- Forum: Introductory Physics Homework Help
-
X
Graphical method to find magnitude and direction
Homework Statement The force vector FA has a magnitude of 90.0 Newtons and points due east. The force vector FB has a magnitude of 135 Newtons and points 75° north of east. Use the graphical method and find the magnitude and direction of (a) FA - FB (give the direction with respect to...- xupe33jrm
- Thread
- Direction Graphical method Magnitude Magnitude and direction Method
- Replies: 30
- Forum: Introductory Physics Homework Help