Recent content by xxclaymanxx

Thank you for your help! it allowed me to go back into my work, and figure out where I wen't wrong. Basically all I did, was i forgot to write an X, and instead wrote a 1...so when I was multiplying both sides by a common demonator, my numbers came out funny. Anyways, I found the error...

1. Given Y = ln [ (x+1)^3/((x^2)-1)^(1/2), find y' 2. I came out with the following answer to this question: (3x-4)/((x^2)-1) How ever, I typed the question into an online derivative calculator (to hopefully check my asnwer as I have no answer key, and want to make sure I'm on the...

1. Given Y = ln [ (x+1)^3/((x^2)-1)^(1/2), find y' 2. I came out with the following answer to this question: (3x-4)/((x^2)-1) How ever, I typed the question into an online derivative calculator (to hopefully check my asnwer as I have no answer key, and want to make sure I'm on the...

Yah, I think I do need some algebra review. That was a really simple error I just made, and this problem took me WAY too long to figure out. Thanks a lot for the quick responses...I just signed up for these forums, and hoped that I would be able to get a respone within the hour, but you...

Ok great thanks, Now for this next part, I guess the thing that is throwing me off is the +1 hanging off the denominator. So, following these steps, I would come out with: -4/16 + x^2 ... which I could then reduce further to: -1/4+x^2 Would that make sense?

derivative of: y=arctan(4/x)! This seems like it should be a very SIMPLE problem, but it has been bugging me for about 2 hours straight now, and I can't figure it out! Would really appreciate some quick help... This is what I've done so far: y'= -4/x^2 / (16/x^2 +1) I don't know if...