Thank you for your help! it allowed me to go back into my work, and figure out where I wen't wrong. Basically all I did, was i forgot to write an X, and instead wrote a 1...so when I was multiplying both sides by a common demonator, my numbers came out funny.
Anyways, I found the error...
1. Given Y = ln [ (x+1)^3/((x^2)-1)^(1/2), find y'
2. I came out with the following answer to this question:
(3x-4)/((x^2)-1)
How ever, I typed the question into an online derivative calculator (to hopefully check my asnwer as I have no answer key, and want to make sure I'm on the...
1. Given Y = ln [ (x+1)^3/((x^2)-1)^(1/2), find y'
2. I came out with the following answer to this question:
(3x-4)/((x^2)-1)
How ever, I typed the question into an online derivative calculator (to hopefully check my asnwer as I have no answer key, and want to make sure I'm on the...
Yah, I think I do need some algebra review. That was a really simple error I just made, and this problem took me WAY too long to figure out.
Thanks a lot for the quick responses...I just signed up for these forums, and hoped that I would be able to get a respone within the hour, but you...
Ok great thanks,
Now for this next part, I guess the thing that is throwing me off is the +1 hanging off the denominator.
So, following these steps, I would come out with:
-4/16 + x^2
...
which I could then reduce further to:
-1/4+x^2
Would that make sense?
derivative of: y=arctan(4/x)!
This seems like it should be a very SIMPLE problem, but it has been bugging me for about 2 hours straight now, and I can't figure it out! Would really appreciate some quick help...
This is what I've done so far:
y'= -4/x^2 / (16/x^2 +1)
I don't know if...