Derivative of a Log function: Y=ln( )

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SUMMARY

The discussion centers on finding the derivative of the logarithmic function Y = ln[(x+1)^3/((x^2)-1)^(1/2)]. The user initially calculated the derivative as (3x-4)/((x^2)-1), but an online derivative calculator provided a different result: (2x-3)/((x^2)-1). The correct approach involves applying the properties of logarithms, specifically ln(a^n/b^k) = ln(a^n) - ln(b^k), which simplifies the differentiation process and clarifies the discrepancy in results.

PREREQUISITES
  • Understanding of logarithmic properties, specifically ln(a^n/b^k)
  • Familiarity with basic differentiation rules in calculus
  • Knowledge of algebraic manipulation techniques
  • Experience with online derivative calculators
NEXT STEPS
  • Study the properties of logarithms in depth, focusing on their application in differentiation
  • Practice differentiation of logarithmic functions using various examples
  • Explore advanced calculus techniques for simplifying complex derivatives
  • Learn how to verify derivative results using online tools and calculators
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Students studying calculus, mathematics educators, and anyone seeking to improve their skills in differentiation and logarithmic functions.

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1. Given Y = ln [ (x+1)^3/((x^2)-1)^(1/2), find y'



2. I came out with the following answer to this question:

(3x-4)/((x^2)-1)


How ever, I typed the question into an online derivative calculator (to hopefully check my asnwer as I have no answer key, and want to make sure I'm on the right path), but it came up with a completely different answer:

(2x-3)/((x^2)-1)

Could anyone point me in the right direction...my answer worked out nicely: factored, canceled etc. but I'm worried its not correct.

Thanks for the check!
 
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I'm not sure how you solved the question initially, but the best way to approach such a question is to use the properties of ln... in particular, remember that ln(a^n/b^k) = ln (a^n) - ln (b^k) and furthermore this is equal to n ln(a) - k ln(b)... Apply these same rules to the original equation and you will get a form that is extremely simple to take the derivative of, and the answer that the online derivative calculator gave you will become apparent :)
 

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