Recent content by XYZ313

This is dumbest question I have ever asked. Hope this is never going to happen again...

spamiam: right, sorry, I'm really dumb x = 1 - π/4 Thank you all for bearing with me...

if I knew what "arctan(x+arctan(x+...))" equals to, I wouldn't be posting this thread...

lurflurf: thank you, this is obvious and not the solution then tan(1-x) = x + arctan(x+arctan(x+...)) and where it is leading?

is it so easy that no one is going even to comment?

what is tan(tanx)? Is above equation some kind of sum of geometric progress?

lurflurf: and then what? tan(π/4) = x + arctan(x+arctan(x+...)) ?

micromass: isn't it the use of inverse operator (tan in this case)? like [FONT="Microsoft Sans Serif"]z=arctan(x+arctan(x+...)) and make the use of tanz? and then use tan addition rule? I am really confused... Can you explain further please?

Can someone please let me know how to find x in π/4=arctan(x+arctan(x+...)) ?

Thank you all! I like Serena: yes you are right, I should have used the word "correspond"; Simon Bridge: yes, the changes are very small, just wrote with delta to make it more readable. Simon Bridge: Serenaphile :smile: I like Serena: which Serena is that? Gossip Girl or Gomez :)...

I attach graphical presentation of the problem. The shadowed area needs to be presented in polar coordinates...

I guess this is which area on polar coordinate system corresponds to the area of Δx * Δy... But which and how you calculate that?

we know that for any (x, y) in Cartesian system, there is such (r, θ) in Polar system, so x = r * cosθ and y = r * sinθ how you can calculate what corresponds to (Δx, Δy) in polar system? how come Δx * Δy = r * Δr * Δθ? Maybe this is very stupid question and has obvious answer...

Done, nvn: Many thanks for your great help.

btw: nice work! is it possible for you to plot forces (vectors) involved?