Recent content by yands

You have to find the range in terms of the initial angle then try to optimize it . That is how I solved it . You have to think why one needs an optimization approach to solve this problem.

There is inconsistency , the questions on the attachment and the problem statement you provided . I would like to help you but there are some ambiguity .

You know cos^2(2x) is non-negative so it means 1+ cos^2(2x) is always positive Use the fact that 1+cos^2(2x) is bounded to evaluate this integral .

Are you sure about your equations ?

It's stated that you have to find the position vector as a function of time. you are correct writing R(0) = 0i + 0j , but this is for the displacement at time t = 0. Think of this as a projectile motion in a gravitational field. R here is a vector.

The total Electric potential due to these two charges at the red cross must be summed as scalars. So write down the potentials as a sum to find the total potentials that's it.

I'm sorry for late response I got lectures :) So you still solving the problem?

You see at the top point V is just Vx so can you relate this to the given information.

Decompose the velocity vector. At the top which component of velocity is zero? Use this idea to find the ratio. As you mentioned

For Sam to catch John both of them should have the same point in space

Can you write the question as it is supposed to be written.

A car start from rest accelerate . Is it constant acceleration? And you have to show us some of your work

Can you try using sin(a+b) = Sin(a)cos(b)...

Ok initially the momentum has only x coordinates . So you have to have zero y-component of momentum after the collision

Think as you set on a long stick and ur friend is away from you who is setting on the stick too the stick is fixed in the middle and the ends oscillate up and down like kids game in the garden. You will see him stationary. Because you both are moving with same angular velocity. So ! Use this...