Recent content by yoghurt54
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Heat loss through an insulated pipe
Homework Statement A pipe of radius R is maintained at temperature T. It is covered in insulation and the insulated pipe has radius r. Assume all surfaces lose heat through Newton's law of cooling \vec{J} = \vec{h} \Delta T, where the magnitude h is assumed to be constant. Show that...- yoghurt54
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- Heat Heat loss Loss Pipe
- Replies: 1
- Forum: Introductory Physics Homework Help
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Charged particle between two conducting plates
I've checked in on this after a day and I'm amazed and grateful at the responses I've gotten. First of all, I'd like to just say that if anyone has any issues with the question itself, I'm not the one who came up with it, nor the supposed value for the induced charge. I was merely stuck on...- yoghurt54
- Post #23
- Forum: Introductory Physics Homework Help
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Charged particle between two conducting plates
That's all she wrote boy! :-) Perhaps I should clarify that the plates are large, which I guess can mean that they can be considered tending to infinite area. Why is it "totally wrong"? Produce your own solution if you see the error.- yoghurt54
- Post #8
- Forum: Introductory Physics Homework Help
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Charged particle between two conducting plates
OK people, I've got it. The two plates are connected by a wire, so they are at equal potential. Note that as the plates are rectangular shaped, so are the equipotentials at each plate. We can call this potential zero. The charges induced are qL and qR. By the uniqueness theorem, the...- yoghurt54
- Post #6
- Forum: Introductory Physics Homework Help
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Charged particle between two conducting plates
The sheet of charge is mentioned in the question. Maybe the plates do not have even charge distributions, but the set-up can be simulated using the sheet charge as an image of the point charge?- yoghurt54
- Post #3
- Forum: Introductory Physics Homework Help
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Charged particle between two conducting plates
Homework Statement Two large conducting plates are separated by a distance 'L', and are connected together by a wire. A point charge 'q' is placed a distance 'x' from one of the plates. Show that the proportion of the charge induced on each plate is 'x/L' and '(L-x)/L'. (Hint: pretend the...- yoghurt54
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- Charged Charged particle Conducting Particle Plates
- Replies: 22
- Forum: Introductory Physics Homework Help
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Show that A is an orthogonal matrix
Homework Statement If {aj} and {bj} are two separate sets of orthonormal basis sets, and are related by ai = \sumjnAijbj Show that A is an orthogonal matrix Homework Equations Provided above. The Attempt at a Solution Too much latex needed to show what I tried...- yoghurt54
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- Matrix Orthogonal
- Replies: 1
- Forum: Calculus and Beyond Homework Help
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How can Stoke's theorem be applied to vector fields?
Yeah you're right. I don't know why I got hung up on this, I guess I was reading too much into it.- yoghurt54
- Post #3
- Forum: Calculus and Beyond Homework Help
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How can Stoke's theorem be applied to vector fields?
Homework Statement \nabla \times f \vec{v} = f (\nabla \times \vec{v}) + ( \nabla f) \times \vec{v} Use with Stoke's theorem \oint _C \vec{A} . \vec{dr} = \int \int _S (\nabla \times \vec{A}) . \vec{dS} to show that \oint _c f \vec{dr} = \int \int _S \vec{dS} \times \nabla...- yoghurt54
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- Stokes Stokes theorem Theorem
- Replies: 2
- Forum: Calculus and Beyond Homework Help
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Graduate Can ALL Vector Fields Be Expressed as a Product?
I'm not sure exactly what you mean, but my understanding of a vector field in this context is that it's a field in a coordinate system where each component is a function of the coordinates of that point, e.g. \vec{A}(x,y,z) = (x^2 - y^2, xz, y^3 + xz^2) -
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Graduate Can ALL Vector Fields Be Expressed as a Product?
Hey - I'm stuck on a concept: Are ALL vector fields expressable as the product of a scalar field \varphi and a constant vector \vec{c}? i.e. Is there always a \varphi such that \vec{A} = \varphi \vec{c} ? for ANY field \vec{A}? I ask because there are some derivations from... -
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Dipole term in a quadrupole expansion
Alrightey then, thank you very much!- yoghurt54
- Post #6
- Forum: Introductory Physics Homework Help
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Dipole term in a quadrupole expansion
The two opposing dipoles - are they the pairings (above) -Q_1,Q_2 and Q_2, -Q_1 (below) ? Is this independent of what the actual magnitudes of the charges are, so long as the two like ones either side of the central one have the same magnitude?- yoghurt54
- Post #4
- Forum: Introductory Physics Homework Help
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Dipole term in a quadrupole expansion
Homework Statement There are three charges arranged on the z-axis. Charge +Q_2 at the origin, -Q_1 at (0,0,a) and -Q_1 at (0,0,-a). Using spherical polar coordinates (i.e the angle \vartheta is between r and the positive z-axis), find the potential at a point with a distance r from the...- yoghurt54
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- Dipole Expansion Term
- Replies: 5
- Forum: Introductory Physics Homework Help
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Energy dissipated by air resistance through integration
Thanks a bunch ehild, but that's not what I wanted. It's pretty trivial to get the height by doing what both you (and I) have done, what I need is a way to determine the ENERGY through integration. This means that I have to integrate the LHS wrt x, which is what I am (still!) stuck on.- yoghurt54
- Post #8
- Forum: Introductory Physics Homework Help