Recent content by yoloswag69

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    Distance needed to walk in order to hear local maximum

    oh right that makes more sense. But when i work it out without the k now i get the distance = -0.27, when the answer is 1.50. I've looked over it and can't see what's wrong. So this is the method i used. (d2 - d1) = n*lambda. d2,d1 and lambda are known so solve for n. Then round n up to the...
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    Distance needed to walk in order to hear local maximum

    nqred said the k is to be left out of the formula now
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    Distance needed to walk in order to hear local maximum

    ohhh i see, you get rad*m i think
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    Distance needed to walk in order to hear local maximum

    If i substitute the rounded value of N back into the equation, i would get d2 - d1 = Nlambda/k. Are d2 and d1 given by sqrt(4 + (1+d)^2) and (1 + d)? If so the equation gives a value of 0.9999 for d. I think so, isn't the value of k given by 2pi/lambda?
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    Distance needed to walk in order to hear local maximum

    Okay i understand now, so you have to find the first "n" after the intial position which points to a maximum. Also just clarifying, in the equation ## k (d_2 - d_1) = n \lambda## k = 2*pi\lambda right? and d2 and d1 are sqrt(5) and 1 respectively? When you substitute these values into the...
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    Distance needed to walk in order to hear local maximum

    10.5 wavelengths wouldn't work though, since it wouldn't indicate a meeting between two crests, so it wouldn't be a maximum?
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    Distance needed to walk in order to hear local maximum

    i think it would, but they would be later local maximums, and the question is asking for first one
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    Distance needed to walk in order to hear local maximum

    d1/d2 = lambda? I am not sure
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    Distance needed to walk in order to hear local maximum

    there should be no relative phase, if their sum needs to be maximum, since through constructive interference the maximum sum is when they are in phase, i think
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    Distance needed to walk in order to hear local maximum

    Sorry the second k is meant to be w. If you use path difference, how do you know what the value of n is?
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    Distance needed to walk in order to hear local maximum

    whats the conflict?
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    Distance needed to walk in order to hear local maximum

    k = 2pi/lambda = 8.96681985 w = 2pi*f = 979pi. But i don't think this is the right way anymore
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    Distance needed to walk in order to hear local maximum

    Okay so i think i may have been on the wrong track. I think you need to use Path difference to calculate the distance travelled. So that means Absolute Value of (1+d) - (sqrt(4 + (1+d)^2) = n*lambda. But now i need to find another equation in d or n to eliminate either one. Does anyone else...
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    Distance needed to walk in order to hear local maximum

    Homework Statement A person stands in an open space listening to the sound from two speakers. The speakers generate sound with a frequency of 489.5 Hz, the speed of sound in air is 343 m/s. The speakers are 2.00 m apart and the person walks away from one of the speakers along a line that is...
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    Pulse pass medium 1 to medium 2 Problem

    Does the frequency change when the pulse passes to the denser medium? Why or why not, i don't really understand.