Recent content by youxcrushxme

Hi everyone I need some help with this problem - The first order rate constant for the decomposition of N2O5 at 70 degrees celsius is 6.82x10-3 s-1 2N2O5 -> 4NO2 +O2 Suppose we start with 25 mmol of N2O5 in a volume of 2L. How many mmol of N2O5 will remain after 2.5 min? I'm not...

I'm having trouble on this problem - Find the volume of the object created by rotating an equilateral triangle around its base. Solve using both shells and cylinders. Any help would be appreciated :)

I know this is probably an easy question but - A 1.10 kg block is held against a spring of force constant 0.2 104 N/m, compressing it a distance of 0.34 m. How fast is the block moving after it is released and the spring pushes it away? If someone could just point me in the right...

So 524.89 = (57.19)(-9.8) - (57.19)a? Or is the 9.8 not supposed to be negative?

Well the apparent weight is given but do I use that number in Newtons or lbs when I'm trying to find acceleratin

So Wa=524.89N and W=560.476N. And using W=mg your apparent mass then is 53.56 and your actual mass is 57.19. Is that right?

So 1 Newton = 0.224808943 lbs...so I multiply the 118 lbs by 0.224808943 and I get 26.526 N and then using weight=mg get mass? Because when I do that I'm getting 2.706 for Wa and that seems waaay off.

So since 126 = mg and g=9.8 then the mass is 12.857. And I did the same thing with the apparent weight and got 12.04. So I have the equation 12.04 = 12.857(-9.8) - (12.857)a and I'm solving for a and getting 10.736 which is getting marked wrong.

So the numbers I'm plugging in for m aren't the right numbers? How do I find them?

Can someone tell me what I'm doing wrong here? When you weigh yourself on good old terra firma (solid ground), your weight is 126 lb. In an elevator your apparent weight is 118 lb. What are the direction and magnitude of the elevator's acceleration? I have Wa = W-ma = mg-ma Wa=118lb...

Ahh, I figured it out, thanks

I'm confused about how I work that in there...I was kind of doing the problem as if the third one wasn't there which is wrong. So I do 7.5/(1.3+3.3+5.1) to get a? And then once I have a how do I find the contact force?

I'm really confused about this problem - As shown in Figure 5-22, a force of magnitude 7.50 N pushes three boxes with masses m1 = 1.30 kg, m2 = 3.30 kg, and m3 = 5.10 kg. (a) Find the magnitude of the contact force between boxes 1 and 2. (b) Find the magnitude of the contact force...

ahh, ok...I got it :) thanks!

Yes...s=2.02 and t=3, so I did st=1/2a(t^2) which gave me a=1.346, and since m=F/a I did 12/1.346 but the answer isn't coming out right...I don't know what I'm doing wrong