Recent content by yttuncel

Hello, By saying "on" I meant switch is open. No, all the current go directly to ground when switch is closed. The current charges up both capacitors very fast due to small time constant(Rin and 0.05μF) to a maximum voltage value of VA. Vout is the voltage on count. The time constant of...

Hello everybody, I am stuck with a circuit that involves voltage controlled switch. Homework Statement The switch is controlled with a square wave generator, Vs1, whose frequency is 100kHz. As far as I know, switch is off when source is on positive phase and vice versa. Therefore, I only...

To gneill, I would say density=ρ=M/ab so what şs dm equal to ? Is it dm=ρ*x*y r2=x2+y2 r=sqrt(x2+y2) So now, ∫dm.r2, but dm is not the one above.. To BetoG93, yes i found it (method to find it with triple Integral) on the net, but that lacked explanation unfortunately

Of course, that was my main and actual argument.

Well as far as I know, it is ML^2/6. But the problem is that I can not find it myself, I don't want to memorize them (the formulas for moment of Inertia).

Oops you are right. It is ΔU=mg(r+L/3)-mg(r+2L/3)-MgL/6

Ok I will definitely think about it. Now we have ρ=M/L and thus dm=(M/L)dz SO I=∫dmr2 I=∫M/Lr2dz Now I got confused how to integrate this one?

ΔU=mg(L/3+r)-mg(2L/3+r)-MgL/3 isn't this the change in gravitational potential energy? So i will equalize 1/2Iw^2 with the one above right? And -I- will be the one in part c right?

Vel. should be max when the right hand sphere is at the bottom. Right sphere's velocity = V1 = w(2L/3+r) Left sphere's velocity = V2 = w(L/3+r) Rod's center of mass's velocity = V3 = w(L/6) ΔK+ΔU=0 ΔK=1/2m(V12+V22)+1/2MV32 ΔU=mg(L/3+r)-mg(2L/3+r)-MgL/3 Anything else I should do?

Btw, your dm and the one i used are the same, arent they?

Wow. But I still can not understand how we can consider a plate as a linear object? I mean, isn't that applicable to one dimensional rods ?

Ok, I got it. For part d) I calculated net torque on the system. τ=-m(r+L/3)+M(L/6)+m(r+2L/3) τ=L/6(2m+M) Now ? τ=I*α How will I relate to velocity? We do not know Δt

Homework Statement A dumbbell is made of a rod length L and mass M, and 2 spheres of radius r and mass m (see figure). The rod is attached at a distance L/3 from the left end to a rotational axis A. The dumbbell is let go under gravity and makes a rotational motion under gravity around the...

Homework Statement Find the moment of Inertia of a cube (mass M, length L) around an axis going through one of the edges. Homework Equations I=Ʃmr2 The Attempt at a Solution Well I imagined the cube is formed of infinitely many square plates. The width of the square plate is dL...

Didnt even see that mentioned in the question :/ Thank you both for your comments and help :) Edit: I think I did it wrong again. Because the final velocity on the table is not equal to the velocity just after the collision Edit2: Ok got it. Lol. Thanks again!