Oh, oops.
x = x0 + v0t + 0.5at2
-30 = V0*6 + 0.5*(-10*62)
-30 = V0*6 - 180
150 = V0*6
V0 = 25
Alright, great, thanks. The second part I can easily do on my own. :)
If I take the base of the skyscraper as the start of the x axis, the ball is thrown up from 30m.
x0 = 30m
xfinal= 0
That completely ignores the up and then down arc of the ball, what am I not understanding?
Homework Statement
A ball is thrown upward from a building 30 meters tall and misses the edge on its way down, hitting the ground 6 seconds after it was thrown.
A) With what speed was it thrown?
B) What is its highest height?Homework Equations
Vf = Vi + at
x = 1/2(Vi + Vf)
x = Vi t + 1/2(at^2)...
Homework Statement
I have conducted a simple lab, that involves getting the distance traveled by a vertically falling weight at certain time intervals. Velocity is calculated for every time interval (distance traveled per time interval). Then I graph velocity versus time to get acceleration...