Recent content by ZamielTheGrey

Oh, oops. x = x0 + v0t + 0.5at2 -30 = V0*6 + 0.5*(-10*62) -30 = V0*6 - 180 150 = V0*6 V0 = 25 Alright, great, thanks. The second part I can easily do on my own. :)

So... x = x0 + v0t + 0.5at2 -30 = V0 + 0.5*(-10*62) -30 = V0 - 180 150 = V0 Is this it?

If I take the base of the skyscraper as the start of the x axis, the ball is thrown up from 30m. x0 = 30m xfinal= 0 That completely ignores the up and then down arc of the ball, what am I not understanding?

Yeah... so we have two missing variable then. An X and Vo :O

Homework Statement A ball is thrown upward from a building 30 meters tall and misses the edge on its way down, hitting the ground 6 seconds after it was thrown. A) With what speed was it thrown? B) What is its highest height?Homework Equations Vf = Vi + at x = 1/2(Vi + Vf) x = Vi t + 1/2(at^2)...

mump

Homework Statement I have conducted a simple lab, that involves getting the distance traveled by a vertically falling weight at certain time intervals. Velocity is calculated for every time interval (distance traveled per time interval). Then I graph velocity versus time to get acceleration...