Recent content by zplot

Thank you

Thank you Bill. With Im[AlgebraicNumber[-4 I, {0, -(1/16)}]] I get Im[AlgebraicNumber[-4 I, {0, -(1/16)}]] and with Simplify[AlgebraicNumber[-4 I, {0, -(1/16)}]] I get AlgebraicNumber[-4 I, {0, -(1/16)}] so no solution yet. Any other...

Hello, From some matrix operations I get "AlgebraicNumber[-4 I, {0, -(1/16)}]" as output. I need to get i/4 and I don't know how. If I write "N[AlgebraicNumber[-4 I, {0, -(1/16)}]]", I get 0. + 0.25 i but it is not what I want neither. I would like to get just i/4 as output. Can...

It works! Thanks a lot, Bill

I don't find any option to remove the frame from a ContourPlot3D graphic in Mathematica. Can anybody help? Thank you.

Great! Thats certainly a much better, simpler and more elegant solution. Thank you very much, Henry.

At the end I arrived at the right solution. (A-lambda I)^k must be zero for some k<n. It comes from the Jordan canonical matrix, where lambda belongs to its spectrum. Logically then, the set {I, A, A^2,..., A^n} is linear dependent. Thank you

Well, I tried to write A=P^(-1) J P where J is a Jordan matrix. Even more, I also tried to put J=N + D where N is nilpotent such that N^n=0 and D diagonal but I could not prove that the set is linear dependent. Thank you for your help. I f you have any further details or ideas I would be pleased.

I need to prove that the set {I, A, A^2,..., A^n} is linear dependent where A is any nxn matrix. The vector space is the set of nxn matrix, considered as a nxn dimensional vector space. Does anybody have an idea how to prove it? Thank you very much.

I have used Karin Erdmann book, I really like it. Thank you very much. I still miss a book focused mainly on exercises.

I am studying Lie Algebras at home by my own, without access to any teacher. Being autodidact, it would much help me to have a book with solved exercises of Lie Algebras or Lie Groups. Does anyone know if is there any book that could help me solving problems, execises? Thank you, Luis

I am sorry but (a.b Mod m) is not iqual to (a Mod m).(b Mod m) being a and b matrix thank you very much

Thank you DaleSpam but it would not work. I will see how could I use Inner. Thanks a lot

Sorry DaleSpam but I don't catch you. I need the product of A and B modulus->n.

I need to multiply 2 matrix in Mathematica but modulus an Integer. The "Modulus->n" option cannot be used with "Dot" function. You can use Modulus-> n with "Inverse" or even "Det" but not with "Dot". It is something strange. How should I do it, then? Any idea? Thank you.