Recent content by zzz3293

I don't believe that would work. I mean you couldn't really take a second indefinite integral because you must add a constant when integrating.

Just to add on a tid bit, Please Excuse My Dear Aunt Sally is a little bit better--Parentheses, Exponents, Multiplication, Division, Addition, Subtraction.

kind of, just remember you don't multiply by something you're adding i.e. 3a+a(6-2a)=9a-2a^2 NOT 18a^2-6a^3 do you follow?

I wouldn't do this in polar, though the x^2+y^2 makes it tempting... Draw out the triangle and figure out the equations for the lines that make it up, use these lines as your bounds for your double integral.

Got it! Now I just need to evaluate which shouldn't be a problem, thanks so much!

I drew it in the xy plane and am looking at it in grapher, I understand the y bounds now, but x and z are still confusing, should x be -3<x<3? I have absolutely no idea how to go about solving for z...

Homework Statement Find the volume of the solid bounded by the cylinder x^2+y^2=9 and the planes y+z=5 and z=1Homework Equations NoneThe Attempt at a Solution My main problem is setting up the integral. So far what I have is 1 as the integrand, my order of integration is dydxdz and my bounds...