Finding the Volume using a triple integral

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Homework Help Overview

The problem involves finding the volume of a solid bounded by a cylinder and two planes, specifically the cylinder defined by x²+y²=9 and the planes y+z=5 and z=1. The context is centered around setting up a triple integral for this volume calculation.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the setup of the triple integral, focusing on the bounds for x, y, and z. There are attempts to clarify the integration order and the appropriate limits based on the geometric constraints of the problem.

Discussion Status

The discussion is ongoing, with participants providing insights into the bounds for integration and questioning assumptions about the limits. Some have suggested drawing sketches to aid understanding, while others have confirmed certain bounds but express uncertainty about others.

Contextual Notes

There are mentions of symmetry in the problem that may simplify the integration process. Participants also note the importance of correctly identifying the limits of integration, particularly for the variable z, which remains a point of confusion for some.

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Homework Statement


Find the volume of the solid bounded by the cylinder x^2+y^2=9 and the planes y+z=5 and z=1

Homework Equations


None

The Attempt at a Solution


My main problem is setting up the integral. So far what I have is 1 as the integrand, my order of integration is dydxdz and my bounds are 0<z<1 and sqrt(9-x^2)<y<5 and I can't figure out x. Is what I have right? What do I need to do? I am really struggling with setting up the bounds for triple integrals
 
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Have you drawn a sketch of the solid? Your typical volume element is dy*dx*dz. What are the bounds for y? I.e., y = ?? to y = ??. Then what are the bounds for x?
 
For the bounds, I obtained 0≤x≤3, -sqrt(9-x^2)≤y≤sqrt(9-x^2), and 1≤z≤5-y. You might want to double check it though.
 
I forgot to mention I went from 0-3 because I multiplied the integrals by 2.
 
I drew it in the xy plane and am looking at it in grapher, I understand the y bounds now, but x and z are still confusing, should x be -3<x<3? I have absolutely no idea how to go about solving for z...
 
Yes, assuming that y is as Dustinfl described.
 
You can use -3 to 3 but since it is a circle you can go from 0 to 3 and multiply by 2 to compensate for -3 to 0. There are 2 planes one is at z=1 and the other is y+z=5. If z=0, then y=5 and if y=0, then z=5, where x can be anything.
 
Got it! Now I just need to evaluate which shouldn't be a problem, thanks so much!
 
Right. In these types of problems the hardest part is figuring out the limits of integration. Also, Dustinfl's suggestion about exploiting the symmetry is a good one that might reduce the chances of making a calculation error.
 

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