Volume with spherical coordinates

  • Thread starter Thread starter aronclark1017
  • Start date Start date
Click For Summary
SUMMARY

The discussion centers on the calculation of volume using spherical coordinates, specifically addressing the relationship between a cone defined by the angle \( a = \pi/3 \) and a sphere represented by the equation \( p = 4 \cos(a) \). Participants express confusion regarding the terminology and the mathematical concepts involved, particularly the definitions of the variables \( a \) and \( p \). The conclusion reached is that the volume in question is bounded by the cone and the spherical cap, with the original poster's intent clarified as seeking to understand this geometric relationship.

PREREQUISITES
  • Spherical coordinates and their representation in three-dimensional space
  • Cylindrical coordinates and their conversion to spherical coordinates
  • Understanding of volume calculations in calculus, specifically involving integrals
  • Familiarity with mathematical notation and terminology, including variables like \( a \) and \( p \)
NEXT STEPS
  • Study the derivation of volume formulas in spherical coordinates
  • Learn about the integration techniques for calculating volumes bounded by surfaces
  • Explore graphical representations of cones and spheres in three-dimensional space
  • Review Stewart's Calculus, particularly section 15.8 on cylindrical and spherical volumes
USEFUL FOR

Students and educators in calculus, mathematicians working with three-dimensional geometry, and anyone involved in computational modeling of geometric shapes.

aronclark1017
Messages
31
Reaction score
4
Homework Statement
Volume above cone a=pi/3
Below sphere p=4 cosa
Relevant Equations
why 0<=a<=pi/2 not working?
I believe that I recall only have to use a part of the polar integral using cylindrical system
 
Last edited:
Physics news on Phys.org
Maybe I'm a bit dumb, but you have to be a bit more specific if you want to receive help. Personally I can't make anything out of this. If you want people to help you, put effort in a clear opening post.
 
Last edited:
  • Like
Likes   Reactions: vela, tensorit, WWGD and 1 other person
It must be because the pointer is spiraling upward as theta increases when using spherical coordinates. However using cylindrical coordinates it's simply using z. I will have to check z values as theta increases when I get a chance. Will also find the example using cylindrical coordinates. Someone must have a 3d animations program. I currently am in the process of drawing only 2d animation.
 
Last edited:
You may need to start at the beginning and describe the problem better. I have no clue what you are talking about.
What is ##a##? ##a=\pi/3## is not a cone; it is a single value: ##a=3.14159265358979/3 = 1.0471975511966##.
What is ##p##? ##p=4 \cos(a)## is not a sphere; it is a single value: ##p=2##.
What "pointer"? "Spiraling"??
What are you talking about?
 
  • Like
Likes   Reactions: tensorit
FactChecker said:
You may need to start at the beginning and describe the problem better. I have no clue what you are talking about.
What is ##a##? ##a=\pi/3## is not a cone; it is a single value: ##a=3.14159265358979/3 = 1.0471975511966##.
What is ##p##? ##p=4 \cos(a)## is not a sphere; it is a single value: ##p=2##.
What "pointer"? "Spiraling"??
What are you talking about?
a is my reference to the angle off the z axis. This is a cone shape for pi/3 for any angle t in the xy plane. The sphere is p=4cosa similarly where p is the spherical pointer and a is the angle off of the z axis.
 
I still don't know what you are talking about. A diagram might help. If you have a question, please don't feed us information a little at a time.
aronclark1017 said:
a is my reference to the angle off the z axis. This is a cone shape for pi/3 for any angle t in the xy plane.
Where does 't' come into this?
aronclark1017 said:
The sphere is p=4cosa similarly where p is the spherical pointer and a is the angle off of the z axis.
If ##a=\pi/3##, then ##p=4\cos(\pi/3)=2##. These are constants. They are not cones or spheres. How are you using them to define cones and spheres? You need to show some equations and, maybe, diagrams.
 
Oh yeah is centered at 0,0,2 so is 2pi for the cone. Here z is dependent on p which appears to require 2 traces of the circle within the xy plane to get to the top of the sphere like it's spiraling upward as theta increases to 2 pi. Although in this cylindrical example #14 only one trace is needed I'm confused. I think is because although z is in terms of r , r reaches its max length with in one trace of the cylinder within the xy plane. Now the question is that if this also can apply to spherical coordinates such as if the former sphere were centered at 1,0,0. I'm not sure is confusing this feng. Even to me expert is trust is master of integrals.

NITRO A65_11112025_190106.webp


NITRO A65_11112025_190125.webp
 
Last edited by a moderator:
Correct me if I'm wrong...
if the sphere is p=sina, centered at 1/2,0,0 then only need theta between -pi/2, pi/2 because is nothing that exists in quadrant 2 and 3 and a for 0, pi/2 . but in the case that the sphere is centered at 0,0,1/2 p=cosa is theta for 0, 2pi and a for 0, pi/2.
this apply to both cylindrical and spherical system with polar equation just have to be spacially careful it seems. I just made a mistake in the where the sphere is centered and panicked.in my confusion.

-pseudo notes by one guy himself all by himself
 
Last edited:
I'm just unclear on exactly what that pointer is doing need to plot many points or see some type of animator what matter any feng else really if no understand these concepts
 
  • #10
You made the effort to post what I presume is the answer guide. Can you post a picture of the actual question?

You talk about a cone at first and the picture shows a cylinder.

I’m with many others. Confused.
 
  • #11
I noticed your supposed solution paper is from 15.8 of Stewart’s calculus book.

IMG_3582.webp


Is it something like this?
 
  • #12
Yes is Stewart 5e calculus section cylindrical and spherical volume is expert of integrals. Justis at the point trying to understand what exactly the pointer is doing. In cases of polar equation on single plane where multiple trace with interval 0, 2pi what exactly the pointer is doing must know. Perhaps only way is to build paint application for 3 dimenions in .net windows form is also expert. But is very busy with documentation methods for larger scale projects and trying to find gym to battle bunyun seizures fro math strain stress.
 
Last edited:
  • #13
FactChecker said:
You may need to start at the beginning and describe the problem better. I have no clue what you are talking about.
What is ##a##? ##a=\pi/3## is not a cone; it is a single value: ##a=3.14159265358979/3 = 1.0471975511966##.
What is ##p##? ##p=4 \cos(a)## is not a sphere; it is a single value: ##p=2##.
I'm pretty sure the OP means the surface in R3 defined by ##\theta = \pi/3## in spherical coordinates, which is a cone, and the sphere given by ##\rho = 4 \cos\theta##. The problem is to find the volume bounded by the cone on the bottom and the spherical cap on top.
 
  • Informative
Likes   Reactions: FactChecker
  • #14
The OP question has been addressed. Thread closed.
 

Similar threads

  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 7 ·
Replies
7
Views
1K
Replies
20
Views
3K
  • · Replies 9 ·
Replies
9
Views
2K
  • · Replies 6 ·
Replies
6
Views
3K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 6 ·
Replies
6
Views
3K
  • · Replies 24 ·
Replies
24
Views
3K
  • · Replies 2 ·
Replies
2
Views
3K