Parametric equation of the intersection between surfaces

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SUMMARY

The discussion focuses on deriving the parametric equation for the intersection of two surfaces: S defined by z = x^2 + y^2 and T defined by z = 1 - y^2. The initial approach involves substituting y = sin(t) to express x and z in terms of t, resulting in x = (1 - 2(sin(t))^2)^0.5 and z = 1 - (sin(t))^2. A more elegant solution is proposed, utilizing the standard parameterization of an ellipse, leading to x = cos(t), y = sin(t)/√2, and z = cos^2(t) + (1/2)sin^2(t).

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[SOLVED] Parametric equation of the intersection between surfaces

Homework Statement



Given the following surfaces:
S: z = x^2 + y^2
T: z = 1 - y^2

Find a parametric equation of the curve representing the intersection of S and T.

Homework Equations



N/A

The Attempt at a Solution



The intersection will be:
x^2 + y^2 = 1 - y^2
x = (1 - 2y^2)^0.5

At this point, I plug in the following parametrization:
y = sin(t)

Which yields:

x = (1 - 2(sin(t))^2)^0.5
y = sin(t)
z = 1-(sin(t))^2 (from the equation for T)

with t = 0..2*Pi.

Judging from a Maple plot this seems to make sense; the curve is a projected ellipse, but due to the x term I have to split it into two separate segments. I'm pretty sure I should be able to use a more elegant solution with a single curve, but I haven't been able to figure it out - any help would be welcome.

Thanks-
 
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In a situation like that it is better not to solve for one of the variables.

Instead, change x2+ y2= 1- y2 to x2+ 2y2= 1, the equation of an ellipse. Then use the "standard" parameterization of an ellipse: x= cos(t), y= sin(t)/\sqrt{2}. Then, of course, you can have either z= cos^2(t)+ (1/2)sin^2(t) or z= 1- (1/2)sin^2(t).
 
Great, thank you.
 

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