Tangential Acceleration and Coefficient of static friction

AI Thread Summary
The discussion revolves around calculating the average tangential acceleration and the coefficient of static friction for the Cajun Cliffhanger ride. Key details include the ride's diameter of 5.3 meters, a final speed of 1.5 m/s reached in 10.1 seconds, and the need to determine the forces involved. Participants suggest using formulas for angular velocity and centripetal acceleration to approach the problem. There is also a request for clarification on measuring forces such as net force, normal force, work, and power in a related context. The conversation highlights the importance of understanding the physics behind rotational motion and friction in practical applications.
Pureness
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Homework Statement


There's a ride called the Cajun Cliffhanger. it's a rotating drum that rotates and makes you stick to the walls. here's are the infomation

The diameter is 5.3m
the speed is 4.2 seconds per rotation at final speed
it takes 10.1 seconds to reach the final speed
You have to find out

Your average tangential acceleration before final speed is reached
the value of the coefficient of static friction between your clothing and the drum wall

Homework Equations





The Attempt at a Solution

 
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Pureness said:

Homework Statement


There's a ride called the Cajun Cliffhanger. it's a rotating drum that rotates and makes you stick to the walls. here's are the infomation

The diameter is 5.3m
the speed is 4.2 seconds per rotation at final speed
it takes 10.1 seconds to reach the final speed
You have to find out

Your average tangential acceleration before final speed is reached
the value of the coefficient of static friction between your clothing and the drum wall

Welcome to PF.

What are your thoughts on how to approach it?

What kind of forces do you think will need to be generated to satisfy the problem?
 
well i found out the final velocity is 1.5 m/s
I think the acceleration at final speed is 0.1m/s2 which i got by using a=(vf-vi)/t which is 1.5m/s/10.1 seconds=0.1m/s2
 
Pureness said:
well i found out the final velocity is 1.5 m/s
I think the acceleration at final speed is 0.1m/s2 which i got by using a=(vf-vi)/t which is 1.5m/s/10.1 seconds=0.1m/s2

Looks to me like

ω = 2*π/ T = 6.283 / 4.1

V = ω *r

so ...

a = V / T = 6.283 * r / (4.1 * 10.1)

Knowing V you can figure the centripetal acceleration and the force available to determine the friction coefficient required.
 
is there a formula or equation for centripetal acceleration?
 
ok thanks for that. i have another part of the question also. it says what is your average tangential acceleration before the final speed is reached. how do i find that
 
thanks. i got another qustion though
can you think of something that can be measured that has these forces in it?
1) a net force
2) a normal force
3) work
4) power
 
  • #10
still need help
 
  • #11
Pureness said:
thanks. i got another qustion though
can you think of something that can be measured that has these forces in it?
1) a net force
2) a normal force
3) work
4) power
A block sliding down a ramp...

Something tells me you might want to be more specific about what you're asking.
 
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