How much matter can you put in space and time?

zeromodz
Messages
244
Reaction score
0
How much matter or energy density can be allowed in space and time before it closes in on itself?
 
Physics news on Phys.org
As most things GR, this depends on a coordinate chart. One such chart is the Schwarzschild solution for an uncharged black hole without angular momentum. This relates the radius of a ball--from which a volume can be implied, to an enclosed mass. See the Wikipedia for the Schwarzschild solution relating mass to radius.

This would put an upper bound on the amount of mass a volume could contain, given the various conditions given above and within the context of classical physics.
 
Last edited:
Phrak said:
As most things GR, this depends on a coordinate chart. One such chart is the Schwarzschild solution for an uncharged black hole without angular momentum. This relates the radius of a ball--from which a volume can be implied, to an enclosed mass. See the Wikipedia for the Schwarzschild solution relating mass to radius.

This would put an upper bound on the amount of mass a volume could contain, given the various conditions given above and within the context of classical physics.

I researched the whole page and I found no direct answer. Shouldn't the actually quantity be invariant? Why can't you just tell me instead of telling me to go look it up?
 
zeromodz said:
How much matter or energy density can be allowed in space and time before it closes in on itself?

A lot depends on what you mean by time and space closing in on itself. If you mean what is the maximum density (p) you can have in a spherical region of space before it collapses into a black hole then the answer is:

p < \frac{3}{32} \, \frac{c^6}{\pi G^3M^2}

It can be seen that from the inequality that the larger the mass, the lower the required density to form a black hole. The converse is that the smaller the radius of the enclosing volume, the greater the density required to to form a black hole and the question becomes how small can the radius of the event horizon of a viable black hole be? Some would conjecture the maximum density would be very roughly the Planck density (a Planck mass contained within a sphere of Planck radius) but there is no real proof of this. It can be also be noted that such a small black hole would evaporate very quickly due to Hawking radiation and so it could not be called stable.

From another point of view, the general consensus is that GR allows all the mass of a fully formed black hole to be contained within a point of zero volume and therefore GR allows the density of the singularity at the centre of a black hole to be infinite, but it is also acknowledged that the laws of physics (as we know them) break down at the black hole singularity and so we do not really know what happens there.
 
Last edited:
OK, so this has bugged me for a while about the equivalence principle and the black hole information paradox. If black holes "evaporate" via Hawking radiation, then they cannot exist forever. So, from my external perspective, watching the person fall in, they slow down, freeze, and redshift to "nothing," but never cross the event horizon. Does the equivalence principle say my perspective is valid? If it does, is it possible that that person really never crossed the event horizon? The...
ASSUMPTIONS 1. Two identical clocks A and B in the same inertial frame are stationary relative to each other a fixed distance L apart. Time passes at the same rate for both. 2. Both clocks are able to send/receive light signals and to write/read the send/receive times into signals. 3. The speed of light is anisotropic. METHOD 1. At time t[A1] and time t[B1], clock A sends a light signal to clock B. The clock B time is unknown to A. 2. Clock B receives the signal from A at time t[B2] and...
From $$0 = \delta(g^{\alpha\mu}g_{\mu\nu}) = g^{\alpha\mu} \delta g_{\mu\nu} + g_{\mu\nu} \delta g^{\alpha\mu}$$ we have $$g^{\alpha\mu} \delta g_{\mu\nu} = -g_{\mu\nu} \delta g^{\alpha\mu} \,\, . $$ Multiply both sides by ##g_{\alpha\beta}## to get $$\delta g_{\beta\nu} = -g_{\alpha\beta} g_{\mu\nu} \delta g^{\alpha\mu} \qquad(*)$$ (This is Dirac's eq. (26.9) in "GTR".) On the other hand, the variation ##\delta g^{\alpha\mu} = \bar{g}^{\alpha\mu} - g^{\alpha\mu}## should be a tensor...

Similar threads

Replies
34
Views
2K
Replies
2
Views
2K
Replies
25
Views
4K
Replies
31
Views
584
Replies
4
Views
2K
Replies
5
Views
1K
Back
Top